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anzhelika [568]
3 years ago
9

Using the data from the table, what is P(3)?!

Engineering
1 answer:
stellarik [79]3 years ago
6 0

Answer:

0.2

Explanation:

I think the mean is 0.4

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A brittle material is subjected to a tensile stress of 1.65 MPa. If the specific surface energy and modulus of elasticity for th
8090 [49]

Answer:

The maximum length of a surface flaw that is possible without fracture is

2.806 \times 10^{-4} m

Explanation:

The given values are,

σ=1.65 MPa

γs=0.60 J/m2

E= 2.0 GPa

The maximum possible length is calculated as:

\begin{gathered}a=\frac{2 E \gamma_{s}}{\pi \sigma^{2}}=\frac{(2)\left(2 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}\right)(0.60 \mathrm{~N} / \mathrm{m})}{\pi\left(1.65\times 10^{6} \mathrm{~N} / \mathrm{m}^{2}\right)^{2}} \\=2.806 \times 10^{-4} \mathrm{~m}\end{gathered}

The maximum length of a surface flaw that is possible without fracture is

2.806 \times 10^{-4} m

7 0
3 years ago
During a cold winter day, wind at 50 km/h is blowing parallel to a 4-m-high and 10-m-long wall of a house. If the air outside is
fenix001 [56]

Answer:

to determine the rate of heat loss from that wall by convection = 12780 watts

Explanation:

8 0
3 years ago
The electron beam in a TV picture tube carries 1015 electrons per second. As a design engineer, determine the voltage needed to
leonid [27]

Answer:

The voltage needed to accelerate the electron beam is 2.46 x 10^16 Volts

Explanation:

The rate of electron flow is given as:

q = 1015 electrons per second

The total current is given by:

Total Current = (Rate of electron flow)(Charge on one electron)

Total Current = I = (1015 electrons/s)(1.6 x 10^-19 C/electron)

I = 1.624 x 10^-16 A

Now, we know that electric power is given as:

Electric Power = Current x Voltage

P = IV

V = P/I

V = 4 W/1.624 X 10^-16 A

<u>V = 2.46 x 10^16 Volts</u>

6 0
3 years ago
Al Quiz
lbvjy [14]
5000! Hope this helps! If you are confused feel free to ask again
4 0
3 years ago
An agricultural manager requires
sp2606 [1]
C, being able to maintain legal information on grant programs
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3 years ago
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