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Helen [10]
3 years ago
6

What happens when a sodium ion is attracted to a chlorine ion?

Chemistry
2 answers:
Jobisdone [24]3 years ago
7 0

They form an ionic compound.
Sliva [168]3 years ago
5 0

when a sodium ion is attracted to a chlorine ion they form an ionic compound

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In Valence Shell Electron Pair Repulsion Theory (VSEPR),
VashaNatasha [74]

Answer: look at the close because that is the answer

Explanation:

7 0
2 years ago
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AYUDENME A CONTESTAR ESTO
Zigmanuir [339]

umm how do you begin answering that ??

8 0
2 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reactionP4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°r
weqwewe [10]

Answer:

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

Explanation:

Enthalpy is denoted by H.

Enthalpy: Total heat change in a chemical reaction is called enthalpy.

The change of entalpy of a reaction is denoted by \bigtriangledown H^\circ_{rxn}

Hass's Law:The change in enthalpy of any process can be determined by calculating the sum of change in enthalpy of each of the steps involved in the process.

g= gas

S= solid

P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}=?

PCl₅(s)→ PCl₃(g)+Cl₂(g) .......(1)       \bigtriangledown H^\circ_{rxn}= +157KJ

P₄(g)+6Cl₂(g)→  4PCl₃(g).............(2)     \bigtriangledown H^\circ_{rxn}= -1207 KJ

If we flip a reaction the value of enthalpy will be change positive to negative or nagative to positive but the numerical value will be remain same.

We need rearrange the equation (1) because in the required equation Cl₂ is on the left side. So we flip the first equation.

PCl₃(g)+Cl₂(g)→PCl₅(s)......(3)          \bigtriangledown H^\circ_{rxn}= -157KJ

Multiplying 4 with equation (3)

4 PCl₃(g)+4Cl₂(g)→4PCl₅(s)......(4)          \bigtriangledown H^\circ_{rxn}=4×( -157)KJ= -628 KJ

Adding equation (2) and (4) we get

P₄(g)+6Cl₂(g)+4 PCl₃(g)+4Cl₂(g)→4PCl₃(g)+4PCl₅(s)    \bigtriangledown H^\circ_{rxn}=( -1207-628)KJ

⇒P₄(g)+10Cl₂(g)→4PCl₃(g)-4PCl₃(g)+4PCl₅(s)      \bigtriangledown H^\circ_{rxn}= - 1835KJ

⇒P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}= -1835 KJ

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

5 0
2 years ago
Which term defines the following: moles of solute mass of solvent in kg?
kramer
The answer is B. molality
7 0
3 years ago
The designations s, p, d, f designate different types of electrons. a. Valence electrons. b. Different electron energy levels. c
azamat

Answer:

C

Explanation:

The electrons in an atom are specifically housed in locations that could be referred to as shells. These shells are the places where we can find an electron.

Now, within each shell, we have different energy levels in which these occupants electrons occupy. These energy levels have different energies and the amount of electrons they can take.

For example, the number of electrons S can take is 2 while that in which d can take is 10

7 0
3 years ago
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