Answer:
Density of copper = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
Explanation:
Given data:
weight of copper metal = 1896 g
Dimensions of block = 8.4 cm, 5.5 cm, 4.6 cm
Density of copper = ?
Will it float to the liquid mercury = ?
Solution:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
volume of coper metal = 8.4 cm × 5.5 cm × 4.6 cm
volume of coper metal =212.52 cm³
d = 1896 g/ 212.52 cm³
d = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
A circuit is a closed loop that electrons can travel in. A source of electricity, such as a battery, provides electrical energy in the circuit. ... The appliance may, for example, provide light or heat or mechanical energy.
Trial 1 has a lower concentration of the reactant because the because the average rate of the reaction is lower.
<h3>What is a reaction?</h3>
The term reaction has to do with the combination of reactants in order to yield products. Now we know that the reaction profile is used to show the interaction that exists between the reactants and the products.
The y-axis of the graph is for the amount while the x axis of the graph is the reaction time. The rate of reaction is the time taken for a given amount of products to appear or for a given amount of reactants to disappear.
Thus, from the graph, we can see that trial 1 has a lower concentration of the reactant because the because the average rate of the reaction is lower.
Learn more about rate of reaction:brainly.com/question/24266729
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Answer: -
24 grams per kilogram.
Explanation: -
We know that
The mixing ratio = actual (measured) mass of water vapor (in parcel) in grams / mass of dry (non water vapor) air (in parcel) in kilogram
The saturation mixing ratio = mass of water vapor required for saturation (in parcel) in grams/ mass of dry (non water vapor) air (in parcel) in kilograms
Relative humidity = actual (measured) water vapor content/ maximum possible water vapor amount (saturation)
Thus saturation mixing ratio = Mixing ratio / relative humidity
= 6 / (25/100)
= 24
Answer:
0.00015dm³
Explanation:
the equation gives
C + O2 — CO2
40min × 60s/1min = 2400s
0.70g/s ÷ 2400s =0.00029g
no of mole = mass/molar mass
molar mass of Co2 = 44g/mol
no of mole = 0.00029/44 = 6.59×10^-6mol
volume at STP since its a gas
1 mol — 22.4dm³
6.59×10^-6 — 22.4×6.59×10^-6/1 = 0.00015dm³
*this is the only way i could think of so am not 100% sure
