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Liula [17]
3 years ago
12

How long does it take for a bicycle traveling 7.0 m/s to come to a stop if the

Physics
2 answers:
Olin [163]3 years ago
7 0
B: 10.5s pc.3.5sbdnshd habsbdjebs
marishachu [46]3 years ago
4 0
  • initial velocity=u=7m/s
  • Final velocity=v=0m/s
  • Acceleration=a=-3.5m/s^2

\\ \rm\Rrightarrow v=u+at

\\ \rm\Rrightarrow t=\dfrac{v-u}{a}

\\ \rm\Rrightarrow t=\dfrac{0-7}{-3.5}

\\ \rm\Rrightarrow t=\dfrac{-7}{-3.5}

\\ \rm\Rrightarrow t=2s

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PLEASE HELP! I'LL GIVE BRAINLEST​
melisa1 [442]

Answer:

Weight = 8.162 Newton.

Explanation:

Given the following data;

Mass = 2.2 kg

Acceleration due to gravity = 3.71 N/kg

To find the weight of the textbook;

Weight = mass * acceleration due to gravity

Weight = 2.2 * 3.71

Weight = 8.162 N

Therefore, the weight of the science textbook in mars is 8.162 Newton.

3 0
3 years ago
How does friction help soccer players
Lena [83]
When soccer players run they are using friction to propell themselves
7 0
3 years ago
Read 2 more answers
A clay ball with a mass of 0.48kg has an initial speed of 4.08m/s it strikes a 3.04kg clay ball at rest and the two balls stick
Rom4ik [11]
Final velocity = 0, thus final kinetic energy is 0
Initial kinetic energy:
0.5mv²
= 0.5 x 0.48 x 4.08²
= 4.0 J
Decrease in kinetic energy = 4 - 0 = 4 Joules
5 0
3 years ago
Susan's 10.0kg baby brother Paul sits on a mat. Susan pulls the mat across the floor using a rope that is angled 30? above the f
elena-s [515]

Answer:

The speed after being pulled is 2.4123m/s

Explanation:

The work realize by the tension and the friction is equal to the change in the kinetic energy, so:

W_T+W_F=K_f-K_i (1)

Where:

W_T=T*x*cos(0)=32N*3.2m*cos(30)=88.6810J\\W_F=F_r*x*cos(180)=-0.190*mg*x =-0.190*10kg*9.8m/s^{2}*3.2m=59.584J\\ K_i=0\\K_f=\frac{1}{2}*m*v_f^{2}=5v_f^{2}

Because the work made by any force is equal to the multiplication of the force, the displacement and the cosine of the angle between them.

Additionally, the kinetic energy is equal to \frac{1}{2}mv^{2}, so if the initial velocity v_i is equal to zero, the initial kinetic energy K_i is equal to zero.

Then, replacing the values on the equation and solving for v_f, we get:

W_T+W_F=K_f-K_i\\88.6810-59.5840=5v_f^{2}\\29.097=5v_f^{2}

\frac{29.097}{5}=v_f^{2}\\\sqrt{5.8194}=v_f\\2.4123=v_f

So, the speed after being pulled 3.2m is 2.4123 m/s

8 0
3 years ago
Ablock of mass m2 on arough horinzontal surfaceis connected to aball of mass m1 by alight weight cord over alight weight frictio
aliya0001 [1]
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3 years ago
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