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S_A_V [24]
3 years ago
7

The pressure exerted at the bottom of a column of liquid is 30 kPa. The height of the

Physics
1 answer:
ella [17]3 years ago
7 0

Answer:

For example, the pressure acting on a dam at the bottom of a reservoir is ... pressure = height of column × density of the liquid × gravitational field ... The density of water is 1,000 kg/m 3.

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Volume of an block is 5 cm3. If the density of the block is 250 g/cm3, what is the mass of the block ?​
9966 [12]

Answer:

1.25kg

Explanation:

Simply multiply volume and density together

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2 years ago
What causes an object to move, change direction or change speed?
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If the distance between the center of two objects is quadrupled. The gravitational
Juliette [100K]

Answer:

F' = F/16

Explanation:

The gravitational force between masses is given by :

F=G\dfrac{m_1m_2}{r^2}

If the distance between the center of two objects is quadrupled, r' = 4r

New force will be :

F'=G\dfrac{m_1m_2}{r'^2}\\\\F'=G\dfrac{m_1m_2}{(4r)^2}\\\\F'=\dfrac{Gm_1m_2}{16r^2}\\\\F'=\dfrac{1}{16}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{16}

So, the new force will change by a factor of 16.

6 0
3 years ago
A system absorbs 194 kj of heat and the surroundings do 120 kj of work on the system. internal eneergy change
notsponge [240]
We can solve the problem by using the first law of thermodynamics, which states that:
\Delta U = Q-W
where
\Delta U is the change in internal energy of the system
Q is the heat absorbed by the system
W is the work done by the system

In our problem, the heat absorbed by the system is Q=+194 kJ, while the work done is W=-120 kJ, where the negative sign means the work is done by the surroundings on the system. Therefore, the variation of internal energy is
\Delta U= Q-W=+194 kJ - (-120 kJ)=+314 kJ
6 0
3 years ago
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