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tatuchka [14]
3 years ago
9

A generator contains a 100-turn coil that rotates 10.0 times per second. if each turn has an area of 0.100 m2 and the magnetic f

ield through the coils is 0.050 t, what is the maximum emf induced in the coil?
Physics
1 answer:
Andrews [41]3 years ago
6 0
We use Lenz's law:
emf = -(NBA)/t ; N is the number of turns, B is the magnetic field, A is the area
t = 1/f = 1/10
emf = (-100 x 0.05 x 0.1) / 0.1
emf = -5 V
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Semmy [17]

Answer:

Kinetic energy of diver at 90% of the distance to the water is 9000 J

Explanation:

Let d is the distance between the position of the diver and surface of the pool.

Initially, the diver is at rest and only have potential energy which is equal to 10000 J.

As the diver dives towards the pool, its potential energy is converting into kinetic energy due to law of conservation of energy, as total energy of the system remains same.

Energy before diving = Energy during diving

(Potential Energy + Kinetic Energy) =  (Kinetic Energy +  Potential Energy)

When the diver reaches 90% of the distance to the water, its kinetic energy

is 90% to its initial potential energy, as its initial kinetic is zero,i.e.,

K.E. = \frac{90}{100}\times10000

K.E. = 9000 J

6 0
3 years ago
If you have a 1.0 m aqueous solution of NaCl, by how much will it increase the water’s boiling point, if KB = 0.512 °C/m? In oth
fgiga [73]

<u>Answer:</u> The elevation in boiling point is 1.024°C.

<u>Explanation:</u>

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=ik_b\times m

where,

i = Van't Hoff factor = 2 (for NaCl)

\Delta T_b = change in boiling point  = ?

k_b = boiling point constant = 0.512^oC/m

m = molality = 1.0 m

Putting values in above equation, we get:

\Delta Tb=2\times 0.512^oC/m\times 1.0m\\\\\Delta Tb=1.024^oC

Hence, the elevation in boiling point is 1.024°C.

5 0
3 years ago
Assume that Michael's teacher has a rule that if a student talks out-of-turn three times in one day, that student must stay in f
olga_2 [115]
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A 60 kg box is lifted by a rope a distance of 10 meters straight up at constant speed. how much power is required to complete th
Nadya [2.5K]
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W=PE=mgh=(60)(9.8)(10)=5880J
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3 years ago
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SCORPION-xisa [38]
Force of gravity. Hope this is correct good luck!!
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