Answer:
99.24 gm of nitrogen .
Explanation:
molecular weight of ammonia = 17 , molecular weight of nitrogen = 28.
2 NH₃(g) + 3 CuO(s) → 1N₂(g) + 3 Cu(s) + 3 H₂O(g)
2 x 17 gm 28 gm
( 34 gm )
34 gm of ammonia forms 28 gms of nitrogen
1 gm of ammonia forms 28 / 34 gms of nitrogen
120.51 gn of ammonia forms 28 x 120.51 / 34 gms of nitrogen
28 x 120.51 / 34 gms
= 99.24 gms of nitrogen will be formed .
The molecular formula of quinine is C20H<span>24N2</span>O<span>2. For every 1 mole of quinine molecule, there are 20 moles of carbon. Simply multiplying 6.0 moles by 20, we get, 120 moles.
Therefore, there are 120 moles of carbon in 6.0 moles of quinine.</span>
Answer:
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Answer:
5.645 × 10⁻²³ g
Solution:
Step 1) Calculate Molar Mass of SH₂;
Atomic Mass of Sulfur = 32 g/mol
Atomic Mass of H₂ = 2 g/mol
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Molecular Mass of SH₂ = 34 g/mol
Step 2: Calculate mass of one molecule of SH₂ as;
As,
Moles = # of Molecules / 6.022 × 10²³
Also, Moles = Mass / M.Mass So,
Mass/M.mass = # of Molecules / 6.022 × 10²³
Solving for Mass,
Mass = # of Molecules × M.mass / 6.022 × 10²³
Putting values,
Mass = (1 Molecule × 34 g.mol⁻¹) ÷ 6.022 × 10²³
Mass = 5.645 × 10⁻²³ g