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Volgvan
3 years ago
8

What is the difference between the energy of spring A, stretched 0.6 meters, and spring B, stretched 0.3 meters, if they have th

e same spring constant? A. Spring A has more potential energy than spring B. B. Spring A has less potential energy than spring B. C. Springs A and B have the same potential energy. D. Springs A and B have the same kinetic energy.
Chemistry
1 answer:
Svetach [21]3 years ago
8 0

Your answer would be A, Spring A has more potential energy.

Potential energy is exactly what it sounds like - energy that has the potential to exist due to stressors, but doesn't yet. In this case, the spring is ready to jump back into its original position however it can't because of it still being stretched, therefore this tension is what creates potential energy.

When you measure potential energy, the one with greater of it is the one where it has more stress being placed on it. In this case, spring A is being stretched furthest so it has the most potential energy.

Hope this helped!

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Typical "hard" water contains about 2.0 x 10–3 mol of Ca2+ per liter. Calculate the maximum concentration of fluoride ion that c
malfutka [58]

Answer:

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Explanation:

Hello,

In this case, for the described situation, we infer that calcium reacts with fluoride ions to yield insoluble calcium fluoride as shown below:

Ca^{+2}(aq)+2F^-(aq)\rightleftharpoons CaF_2(s)

Which is typically an equilibrium reaction, since calcium fluoride is able to come back to the ions. In such a way, since the maximum amount is computed via stoichiometry, we can see a 1:2 mole ratio between the ions, therefore, the required maximum amount of fluoride ions in the "hard" water (assuming no other ions) turns out:

[F^-]_{max}=2.0x10^{-3}\frac{molCa^{2+}}{L}*\frac{2molF^-}{1molCa^{2+}}  \\

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Best regards.

8 0
3 years ago
Question 10 OT 20
Airida [17]

Answer:

B) is reduced.

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced and it is oxidizing agent.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized and it is reducing gent.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

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