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Serjik [45]
3 years ago
9

When 50.0 g of 0.200 M NaCl(aq) at 24.1 °C is added to 100.0 g of 0.100 M AgNO3(aq) at 24.1 °C in a calorimeter, the temperature

increases to 25.2 °C as AgCl(s) forms. Assuming the specific heat of the solution and products is 4.20 J/g °C, calculate the approximate amount of heat in joules produced.
Chemistry
1 answer:
Annette [7]3 years ago
4 0

Answer:

Q = 693 J

Explanation:

NaCl (aq) + AgNO₃ (aq) → AgCl (s) + NaNO₃ (aq)

Q = mcΔT

Q: heat

m: mass

c: specific heat

ΔT: temperature variation

Q = (50.0g + 100.0g) x (4.20 J/g°C) x (25.2°C - 24.1°C)

Q = 693 J

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There is some info missing. I looked at the question online.

<em>The air in a cylinder with a piston has a volume of 215 mL and a pressure of 625 mmHg. If the pressure inside the cylinder increases to 1.3 atm, what is the final volume, in milliliters, of the cylinder?</em>

Step 1: Given data

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