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4vir4ik [10]
3 years ago
5

The pka value for the carboxylic acid group in acetic acid is 4.75. write the predominant structure of acetic acid at (a ph=1, (

b ph=7

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
7 0
Hello!

A) At pH=1

This pH is lower than the value for the pKa, so Acetic acid wouldn't be ionized, but the equilibrium would be displaced to CH₃COOH

CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the left)

The chemical structure for CH₃COOH is the first one in the attached images.

B) At pH=7

This pH is higher than the value for the pKa, so Acetic acid would be ionized, and the equilibrium would be displaced to CH₃COO⁻

CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the right)

The chemical structure for CH₃COO⁻ is the second one in the attached images.

Have a nice day!

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N2 + 3H2 + 2NH3 .
HACTEHA [7]

Answer:

7

Explanation:

7 0
3 years ago
Force = 2.32 N<br> Acceleration = 0.19 m/s2<br> Mass= ?
Mkey [24]

mass = 12.2 kg

Explanation:

To find the mass we use the following formula (Newton's Second Law of Motion):

force = mass × acceleration

mass = force / acceleration

mass = 2.32 N / 0.19 m/s²

mass = 12.2 kg

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3 0
3 years ago
A solution contains 0.60 mg/ml mn2+. what minimum mass of kio4 must me added to 5.00 ml of the solution in order to completely o
azamat
The given solution of Mn²⁺ is 0.60 mg/mL.
Hence mass of Mn²⁺ in 5 mL of solution = 0.60 mg/mL x 5 mL = 3 mg

Molar mass of Mn = 54.9 g/mol
Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol

The balanced equation for the reaction is,
2Mn²⁺ + 5KIO₄ + 3H₂O → 2MnO₄⁻ + 5KIO₃ + 6H⁺

The stoichiometric ratio between Mn²⁺ and KIO₄ is 2 : 5

Hence, moles of KIO₄ reacted = 5.46 x 10⁻⁵ mol x (5 / 2)
                                                 = 13.65 x 10⁻⁵ mol
Molar mass of KIO₄ = 230 g/mol

Hence needed mass of KIO₄ = 13.65 x 10⁻⁵ mol x 230 g/mol
                                               = 0.031395 g
                                               = 31.395 mg
                                               ≈ 31.4 mg
5 0
3 years ago
For each situation below, state whether water will move into the cell, move out of the cell, or stay the same.
Firdavs [7]
Water moves from an area of higher water potential (aka. "more water" in simple language) to an area of lower water potential (aka. "less water" in simple language).

For A, cells in carrots have water stored in their cytoplasm, where many soluble substances may be found (e.g. sodium ions). On the other hand, pure water has no other soluble substances other than the water molecules (I.e. H2O). Pure water will thus have a higher water potential as compared to the water in carrot cells, and so, water will move from pure water into the carrot cells via osmosis down a concentration gradient.

B. Corn syrup is water that has high concentrations of sugars, thus it is very likely to have a lower water potential than the cells of carrots. Water will move from within the cells of carrots and out to the corn syrup, down a concentration gradient.

C. The water in carrot cells will stay the same, since carrot cells have the same water potential as the surrounding solution which has the same water potential as cytoplasm.

Hope this helps! :)
8 0
3 years ago
State with reasons, whether sulphur dioxide is acting as an oxidizing agent or a reducing agent in each of the following reactio
evablogger [386]

Answer:

A) oxidizing agent is SO2

B) NaClO is the oxidizing agent

Explanation:

A) This is a redox reaction in which oxidation and reduction occur simultaneously.

Thus, in 2H2S(g) + SO2(g) -> 2H2O(l) + 3S(s);

H2S is reduced as follows;

H2S → S + 2H+ + 2e−

We can see that SO2 has been reduced while H2S gets oxidized since it has changed state from - 2 to 0 . Thus sulphur dioxide is the oxidizing agent.

B) SO2(g) + H2O(l) + NaClO(aq) -> NaCl(aq) + H2SO4(aq)

In this, SO2 undergoes oxidation and NaClO is the oxidizing agent

4 0
3 years ago
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