Using the following formula for linear-motion, the missing variable can be solved:
s = Vi * t + 1/2 (a * t^2)
Where: s = displacement = 29.7 m
Vi = initial velocity = 8.5 m/s
a = acceleration = 9.8
t = time = ?
Substituting:
29.7 = 8.5t + 1/2 (9.8*t^2)
29.7 = 8.5t + 4.9t^2
Dividing both sides by 4.9:
6.06 = 1.73t + t^2
t^2 + 1.73t - 6.06 = 0
(t - 1.74)(t + 3.48) = 0
t = 1.74s
From the above values, the correct answer is 1.74 seconds.
Answer:
Neural Engineering and Tissue Engineering
Explanation:
• BME is Biomedical Engineering. It has various topics such as Anantomy, Physiology, Neural Engineering and Tissue engineering, Medical mechanisation and others.
Answer:
So we have a measure in grams, we can start with something like:
143.523 grams.
Now we want this measurement to be precise to the nearest tenth of a gram.
The nearest tenth of a gram is the first digit after the decimal point, then the digits that come after this are not useful, because they are outside our precision range.
Then we must write our measurement as:
143.5 grams
Where the digit that came after the 5 was a 2, so we rounded down.
Answer:
6.54 × 10⁻⁵ Pa-s
Explanation:
Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m
Since F = μAu/y
F/A = μu/y where F/A = force per unit area
Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²
So, μ = F/A ÷ u/y
substituting the values of the variables into the equation, we have
μ = F/A ÷ u/y
μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m
μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s
μ = 6.54 × 10⁻⁵ Ns/m²
μ = 6.54 × 10⁻⁵ Pa-s
