Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
The value of x would be
or 
Step-by-step explanation:
Given,
x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain 5% gravel mixture,
Thus, gravel G in x ton + gravel in y ton = gravel G in the resultant mixture,
⇒ 0.1x + 0.02y = 0.05(x+y),
0.1x - 0.05x = 0.05y - 0.02y
0.05x = 0.03y

Now, resultant mixture is z ton,
i.e. 

From equation (1),




I believe it is 17.0, I hope this helps some
Answer:
175-176 passes are completed in a season
Step-by-step explanation:
Answer:
2 3/10, 2.59, 24
Step-by-step explanation: