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OverLord2011 [107]
3 years ago
15

What is the name of the plate to the west and directly adjacent to the plate on which Chile is located?

Physics
1 answer:
Ksenya-84 [330]3 years ago
6 0
<h2>Answer: Nazca plate</h2>

Explanation:

The Nazca plate is an oceanic tectonic plate that is found in the Pacific Ocean off the west coast of South America, specifically in front of the north and central coast of Chile and the entire coastline of Peru, Ecuador and Colombia. This plate is in constant motion, which causes it to sink under the South American (phenomenon known as subduction).

It is mainly because of this subduction process that this region has a lot of seismic activity. Another important aspect is that thanks to these movements, the Andes mountain range and the Peruvian-Chilean fossa originated.

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Lostsunrise [7]
B.) Speeding up......
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3 years ago
A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
enot [183]

Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

acceleration a = ∆v/t

a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

a = -5.099974500127

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

7 0
3 years ago
PLEASE HELP!!!!!
never [62]

Answer:

The answer is A

Explanation:

When a rockets thrusters push on the ground the ground pushes back on the rocket with equal force in the opposite direction. Hence the rocket takes off.

Newtons third law of motion states, for every action there is an equal and opposite reaction.

7 0
2 years ago
Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. It has a centripetal force. F acting on it. If bod
cluponka [151]

Answer:

The centripetal force on body 2 is 8 times of the centripetal force in body 1.

Explanation:

Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. The centripetal force acting on it is given by :

F=\dfrac{mv^2}{r}

Body 2 has a mass 2m and its moving in a circle of radius 4r at a speed 4v. The centripetal force on body 2 is :

F'=\dfrac{2m\times (4v)^2}{4r}\\\\F'=\dfrac{2m\times 16v^2}{4r}\\\\F'=8\dfrac{mv^2}{r}\\\\F'=8F

So, the centripetal force on body 2 is 8 times of the centripetal force in body 1.

8 0
3 years ago
Find the displacement in meters a runner would travel in 5 hours at an average velocity of 12km/h to the southwest
vova2212 [387]

Answer:

60,000m

Explanation:

Convert km/h to m/s by multiplying with 1000/3600.

Convert hours to seconds by multiplying with 3600.

Because displacement is a vector quantity and deals with the shortest distance between points, simply plug it into the equation s=vt.

8 0
3 years ago
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