Answer:
a. 3-methylbutan-2-ol
b. 2-methylcyclohexan-1-ol
Explanation:
For this reaction, we must remember that the hydroboration is an <u>"anti-Markovnikov" reaction</u>. This means that the "OH" will be added at the <em>least substituted carbon of the double bond.</em>
In the case of <u>2-methyl-2-butene</u>, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore <u>the "OH" will be added to carbon three</u> producing <u>3-methylbutan-2-ol</u>.
For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore<u> the "OH" will be added to carbon 2</u> producing <u>2-methylcyclohexan-1-ol</u>.
See figure 1
I hope it helps!
The symbol for dinitrogen trisulfide is N2S3
Answer: The final temperature of nickel and water is .
Explanation:
The given data is as follows.
Mass of water, m = 55.0 g,
Initial temp, ,
Final temp, = ?,
Specific heat of water = 4.184 ,
Now, we will calculate the heat energy as follows.
q =
=
Also,
mass of Ni, m = 15.0 g,
Initial temperature, ,
Final temperature, = ?
Specific heat of nickel = 0.444
Hence, we will calculate the heat energy as follows.
q =
=
Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.
= -()
=
Thus, we can conclude that the final temperature of nickel and water is .
Answer:
182.156g
Explanation:
grams = 49/.269 = 182.156g needed