Answer:
The magnitude of the induced Emf is 
Explanation:
The width of the truck is given as 79inch but we need to convert to meter for consistency, then
The width= 79inch × 0.0254=2.0066 metres.
Now we can calculate the induced Emf using expresion below;
Then the 
Where B= magnetic field component
L= width
V= velocity
=(40*10^-6) × (42) × (2.0066)
=0.003371V
Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V
Answer:
distance must be = 330 × 5/2
= 330×2.5
=825m
B. Kilopascals.
A kilopascal equals to 1,000 pascals; and a pascal is equal to a force of 1 newton per square meter.
Meanwhile,
- a gram and a kilogram are both units of measurement for mass, and
- a newton is a unit of measurement for force.
Answer:
almost 100% positive its B but dont take me up on it
Let us list out what we know from the question.
Initial Velocity
since the piton is 'dropped'.
Vertical Displacement of the piton D = 215 m
Acceleration due to gravity 
Final Velocity 
Using the equation,
and plugging in the known values, we get

Simplifying by taking square-root on both sides gives us 
Thus, the speed of the piton just before striking the ground is 65 m/s.