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3 years ago

What causes the Brownian motion of particles in a colloid?

Chemistry

1 answer:

LekaFEV [45]3 years ago

6 0

<u>Answer:</u>

The correct answer option is a) collisions between the particles and surrounding molecules.

<u>Explanation:</u>

The collisions between the particles and surrounding molecules causes the Brownian motion of particles in a colloid.

Brownian motion is the irregular movement of the microscopic particles in a fluid which bombard into each other.

It basically is the result of the molecules of a dispersion medium colliding with the dispersed particles of the phase.

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Which temperature and pressure are used as standards for gases?

qwelly [4]

Answer:

0°C and 1 atm

Explanation:

This are the conditions of temperature and pressure defined by IUPAC as standard.

But also, the definition used by the NIST considerates a temrperature of 20°C and a pressure of 1 atm

3 0

3 years ago

Read 2 more answers

For the chemical equation SO 2 ( g ) + NO 2 ( g ) − ⇀ ↽ − SO 3 ( g ) + NO ( g ) the equilibrium constant at a certain temperatur

MakcuM [25]

Answer:

Moles of NO₂ = 0.158

Explanation:

SO 2 ( g ) + NO 2 ( g ) ⇄ SO 3 ( g ) + NO ( g )

According to the law of mass equation

$K_{c}$ = $\frac{[SO_{3} ][NO]}{[SO_{2}][NO_{2} ]}$

⇒ 3.10 = $\frac{(1.00)(1.00)}{(2.30) [NO_{2} ]}$ At equilibrium [SO₃] = [NO]

⇒ [NO₂] = $\frac{1}{6.3}$

⇒ [NO₂] = 0.158

So. number of moles of NO₂ at equilibrium added = 0.158

8 0

3 years ago

Given the Henry’s law constant for O2(4.34*109Pa) at 25° C, calculate the molar concentration of oxygen in air-saturated and O2s

Flauer [41]

This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, $2.67\times 10^2mol/L$

Explanation :

As we know that,

$C_{O_2}=k_H\times p_{O_2}$

where,

$C_{O_2}$ = molar solubility of $O_2$ = ?

$p_{O_2}$ = partial pressure of $O_2$ = 0.2 atm = 1.97×10⁻⁶ Pa

$k_H$ = Henry's law constant = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

$C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)$

$C_{O_2}=8.55\times 10^3g/L$

Now we have to molar concentration of oxygen.

Molar concentration of oxygen = $\frac{8.55\times 10^3g/L}{32g/mol}=2.67\times 10^2mol/L$

Therefore, the molar concentration of oxygen is, $2.67\times 10^2mol/L$

8 0

3 years ago

What causes waves to occur?

Flura [38]

Answer:

definitely the wind lol

5 0

3 years ago

When the procedure calls for making a more dilute solution of an acid, or mixing an acid with other solutions, what is the corre

Fed [463]

Answer:

The correct order it b. always add acid last.

Explanation:

Adding acid first could result on a violent reaction and heat or fumes can be generated. The best approach is to always add all the water or non-acid component first, or add a significant portion before adding the acid slowly to the mixture.

7 0

3 years ago