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2 years ago

What causes the Brownian motion of particles in a colloid?

Chemistry

1 answer:

LekaFEV [45]2 years ago

6 0

<u>Answer:</u>

The correct answer option is a) collisions between the particles and surrounding molecules.

<u>Explanation:</u>

The collisions between the particles and surrounding molecules causes the Brownian motion of particles in a colloid.

Brownian motion is the irregular movement of the microscopic particles in a fluid which bombard into each other.

It basically is the result of the molecules of a dispersion medium colliding with the dispersed particles of the phase.

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9. What is the total number of grams of NaOH (formula mass = 40.) needed to make 1.0 liter of a 0.20 M solution?

xxTIMURxx [149]

Answer:

8 gram

Explanation:

in case of NaOH, normality=molarity

so normality=molarity×acidity or basicity(in case of NaOH it's 1)

then

weight of NaOH required = volume in ml × equivalent weight × normality / 1000

1000× 40× 0.2/1000

=8 gram

3 0

2 years ago

Using the average initial pH of your acetic acid solutions (2.96), and the average molarity of those solutions(.0602), calculate

Orlov [11]

Answer : The value of Ka for acetic acid is, $2.03\times 10^{-5}$

Explanation :

The chemical formula of acetic acid is, $CH_3COOH$ .

The chemical equilibrium reaction will be:

$CH_3COOH\rightleftharpoons CH_3COO^-+H^+$

Given:

pH = 2.96

First we have to calculate the concentration of hydrogen ion.

$pH=-\log [H^+]$

$2.96=-\log [H^+]$

$[H^+]=1.096\times 10^{-3}M$

That means,

$[H^+]=[CH_3COO^-]=1.096\times 10^{-3}M$

$[CH_3COOH]=0.0602-(1.096\times 10^{-3})=0.0591M$

The expression for reaction is:

$K_a=\frac{[CH_3COO^-][H^+]}{[CH_3COOH]}$

$K_a=\frac{(1.096\times 10^{-3})\times (1.096\times 10^{-3})}{0.0591}$

$K_a=2.03\times 10^{-5}$

Thus, the value of Ka for acetic acid is, $2.03\times 10^{-5}$

3 0

3 years ago

What can you assume about the anions in the ionic compound copper(II) fluoride? A. The charge on the ionic compound is 2+.

erastova [34]

The answer is C, because if the copper has a +2 charge, the fluoride must have a -2 charge in order to cancel out.

4 0

3 years ago

The vapor pressure of benzene at 298 K is 94.4 mm of Hg. The standard molar Gibbs free energy of formation of liquid benzene at

horsena [70]

Answer:

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

Explanation:

Bringing out the parameters mentioned in the question;

Vapor pressure = 94.4 mm of Hg

The vaporization reaction is given as;

C₆H₆(l) ⇄ C₆H₆(g)

Equilibrium in terms of activities is given by:

K = a(C₆H₆(g)) / a(C₆H₆(l))

Activity of pure substances is one:

a(C₆H₆(l)) = 1

Assuming ideal gas phase activity equals partial pressure divided by total pressure. At standard conditions

K = p(C₆H₆(g)) / p°

Where p° = 1atm = 760mmHg standard pressure

We now have;

K = 94mmHg / 760mmHg = 0.12421

Gibbs free energy is given as;

ΔG = - R·T·ln(K)

where R = gas constant = 8.314472J/molK

So ΔG° of vaporization of benzene is:

ΔvG° = - 8.314472 · 298.15 · ln(0.12421)

ΔvG° = 5171J/mol = 5.2kJ/mol

Gibbs free energy change of reaction = Gibbs free energy of formation of products - Gibbs free energy of formation of reactants:

ΔvG° = ΔfG°(C₆H₆(g)) - ΔfG°(C₆H₆(l))

Hence:

ΔfG°(C₆H₆(g)) = ΔvG°+ ΔfG°(C₆H₆(l))

ΔfG°(C₆H₆(g)) = 5.2kJ/mol + 124.5kJ/mol

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

6 0

3 years ago

Dissolving salt in water reduces the intermolecular forces between water molecules. What most likely happens to the surface tens

Svetllana [295]

If we dissolve salt in water they will reduce the intermolecular forces between water molecule and this will decrease the surface tension.

Surface tension is due to cohesive forces (the forces between molecules of same substance) hence as cohesive forces decreases the surface tension also decreases

7 0

3 years ago

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