If 50 liters of carbon dioxide gas are produced by the reaction below at 273 Kand 100 atm, how oxygen gas were used the reaction
? 2 CO(g) + O2(g) ----> 2 CO2(g)
1 answer:
Using the ideal gas equation:
pV = nRT
n = pV / RT
1atm = 101325Pa, so p = 10132500Pa
1L = 0.001m^3, so V = 0.050m^3
R = 8.214 (ideal gas constant)
T = 273K
Hence moles of CO2 = (10132500 * 0.050) / (8.314 * 273) = 223.2101553
Reaction ratio between oxygen and CO2 is 1:2
Hence moles of O2 = 223... / 2 = 112 moles (3sf)
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