Answer:
(a). The total moment of inertia of the system is 0.0233 kg-m².
(b). The kinetic energy is 0.0011 J.
Explanation:
Given that,
Mass of each particle m= 0.85 kg
Length = 5.6 cm
Mass of each rod M= 1.2 kg
Angular speed = 0.30 rad/s
The moment of inertia of the rod between axis of rotation and mass is
The moment of inertia of the rod between masses about center of mass is
Moment of inertial of the rod between masses about point O is
Moment of inertia of two masses is
(a). We need to calculate the total moment of inertia of the system
Using formula of moment of inertia
Put the value into the formula
Put the value into the formula
(b). We need to calculate the kinetic energy
Using formula of kinetic energy
Put the value into the formula
Hence, (a). The total moment of inertia of the system is 0.0233 kg-m².
(b). The kinetic energy is 0.0011 J.