<u>Answer:</u> The mass of iron in the ore is 10.9 g
<u>Explanation:</u>
We are given:
Mass of iron (III) oxide = 15.6 g
We know that:
Molar mass of Iron (III) oxide = 159.69 g/mol
Molar mass of iron atom = 55.85 g/mol
As, all the iron in the ore is converted to iron (III) oxide. So, the mass of iron in iron (III) oxide will be equal to the mass of iron present in the ore.
To calculate the mass of iron in given mass of iron (III) oxide, we apply unitary method:
In 159.69 g of iron (III) oxide, mass of iron present is 
So, in 15.6 g of iron (III) oxide, mass of iron present will be = 
Hence, the mass of iron in the ore is 10.9 g
0.600
D) 0.600 is the final concentration of the solution of KCl.
V1 = 50.0 mL.
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The statements describe a spring at its equilibrium position is the elastic potential energy is zero, the displacement of the spring is at a maximum and the net force acting on the spring is zero.
<h3>What is the equilibrium position?</h3>
A body is in equilibrium when the sum of all forces acting on it equals zero. According to Newton's First Law, when resulting from the laws that act on a body that remains in a state of restriction or in motion in its motion, it remains uniformly null.
In this case the only statements that match the definition of equilibrium position are:
- The elastic potential energy is zero.
- The displacement of the spring is at a maximum.
- The net force acting on the spring is zero.
See more about equilibrium position at brainly.com/question/10374921
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5.75g
Explanation:
Given parameters:
Number of atoms = 1.505 x 10²³atoms
let us find the number of moles and mass of this atom.
Solution:
The mole is convenient unit for reporting measurements in chemistry. It allows us to make mathematical calculations:
one mole of substance contains 6.02 x 10²³atoms
Number of moles of Na given =
= 0.25moles
Mass of Na atom given = number of moles x molar mass
Molar mass of Na= 23g/mole
Mass of Na = 0.25 x 23 = 5.75g
learn more:
Number of moles brainly.com/question/1841136
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