Explanation:
For what I can see, is missing the concentration of [Ag+] in the half-cell. To calculate it:
Niquel half-cell
Oxidation reaction:
Assuming T=298 K / R=8.314 J/mol K / F=96500 C
Silver half-cell
Reduction reaction:
Assuming T=298 K / R=8.314 J/mol K / F=96500 C
It is in period 3
It is in group 17
It is a chlorine atom because it has 17 electrons which means the atomic number is 17
It was J. J. Thomson (Joseph John Thomson) i believe!!
Answer:
A)
Explanation:
It estimates the probability of extinction.
Answer:
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Explanation:
The concentration of the solution is given by :
We have:
Concentration of copper (II) nitrate solution =
The volume of solution = 4.12 mL
1 mL= 0.001 L
Moles of copper (II) nitrate in solution = n
Moles of copper (II) nitrate in solution = 0.0099292 mol
1 Mole of copper(II) nitrate has 1 mole of copper then 0.0099292 moles of copper(II) nitrate will have :
Mass of 0.0099292 moles of copper:
This mass of copper present in the solution is the theoretical mass of copper present in the given copper(II) nitrate solution.
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment