You hear a sound in the distance. Suddenly the sound gets deeper, decreasing in pitch. Which can you assume about the sound wave
1 answer:
You might be interested in
Answer:
(a). If z = 0, The electric field due to the rod is zero.
(b). If z = ∞, The electric field due to the rod is .
(c). The positive distance is
(d). The maximum magnitude of electric field is
Explanation:
Given that,
Radius = 2.00 cm
Charge = 4.00 mC
(a). If the radius and charge are R and Q.
We need to calculate the electric field due to the rod
Using formula of electric field
Where, Q = charge
z = distance
If z = 0,
Then, The electric field is
(b). If z = ∞, z>>R
So, R = 0
Then, the electric field is
(c). In terms of R,
We need to calculate the positive distance
If
Then,
Taking only positive distance
(d). If R = 2.00 and Q = 4.00 mC
We need to calculate the maximum magnitude of electric field
Using formula of electric field
Hence, (a). If z = 0, The electric field due to the rod is zero.
(b). If z = ∞, The electric field due to the rod is .
(c). The positive distance is
(d). The maximum magnitude of electric field is
The equilibrium condition allows finding the results for the forces of the system are
a) The free body diagram is in the attachment
b) The normal force is N = 737 N
c) The mass of the table is 10.2 kg
Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it is called the equilibrium condition
∑ F = 0
Where the bold letters indicate vectors, F is the external forces
a) A free body diagram is a scheme of the forces without the details of the bodies, in the attachmentt we see a free body diagram of the system.
b) The reaction force of the ground is applied in each of the legs of the table, in general this force has the same magnitude in each leg, therefore in Newton's second law we can place it as a single force
N = N₁ + N₂ + N₃ + N₄₄
Let's apply the equilibrium condition
N - = 0
N =
N =
They indicate the pose of the boy is 65 kg, for the weight of the table of a laboratory table is approximately 100 N
N = 65 9.8 + 100
N = 737 N
c) To calculate the mass of the table we use the relation
W = g
e = 10.2 kg
In conclusion using the equilibrium condition we can find the results for the forces are
a) The free body diagram is in the attachment
b) The normal force is N = 737 N
c) The mass of the table is 10.2 kg
Learn more here: brainly.com/question/19860811
