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Scrat [10]
4 years ago
11

The elements on the Periodic Table are arranged in order of increasing

Chemistry
1 answer:
Nookie1986 [14]4 years ago
6 0
<span>The elements on the Periodic Table are arranged in order of increasing "Atomic number"

In short, Your Answer would be Option B

Hope this helps!</span>
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Think about a wooden chair and a balloo. What do these two objects always have in common
vovangra [49]
A. Both are made of atoms.
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4 years ago
Read 2 more answers
What is the name of the ionic compound, NaOH
Arisa [49]
SODIUM HYDROXIDE

IUPAC ID


Sodium hydroxide

Sodium oxidanide

7 0
3 years ago
(a) How many stereoisomers are possible for 4,4-dimethyl-1,2-cyclopentanediol?
Monica [59]

Answer:

(a) 4 stereoisomers: (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. (b) (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol (c) No, they are optically inactive.

Explanation:

(a) The stereoisomers possible for 4,4-dimethyl-1, 2-cyclopentanediol are (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. Their structures are shown in the attached file.

(b) The oxidation reaction that occurs between 4,4-dimethylcyclopentene and osmium tetroxide produces (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol. Their structures are also shown in the attached file.

(c) The products of the oxidation reaction in (b) are optically inactive because the compounds contain plane of symmetry that makes them optically inactive compound.

Download docx
5 0
4 years ago
A 100.0-g sample of water at 27.0oC is poured into a 71.0-g sample of water at 89.0oC. What will be the final temperature of the
Sedbober [7]

<u>Answer:</u> The final temperature will be 52.74^oC

<u>Explanation:</u>

Calculating the heat released or absorbed for the process:

q=m\times C\times (T_2-T_1)

In a system, the total amount of heat released is equal to the total amount of heat absorbed.

q_1=-q_2

OR

m_1\times C\times (T_f-T_1)=-m_2\times C\times (T_f-T_2) ......(1)

where,

C = heat capacity of water = 4.184J/g^oC

m_1 = mass of water of sample 1 = 100.0 g

m_2 = mass of water of sample 2 = 71.0 g

T_f = final temperature of the system = ?

T_1 = initial temperature of water of sample 1 = 27^oC

T_2 = initial temperature of the water of sample 2 = 89.0^oC

Putting values in equation 1, we get:

100.0\times 4.184\times (T_f-27)=-71.0\times 4.184\times (T_f-89)\\\\171T_f=9019\\\\T_f=\frac{9019}{171}=52.74^oC

Hence, the final temperature will be 52.74^oC

6 0
3 years ago
What type of reaction is represented here:<br> 2K + Ca(OH)2 → 2KOH+ Ca
Anton [14]

Answer:

can you show me a picture of that element graph pls i dont really understand it

5 0
3 years ago
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