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Shalnov [3]
3 years ago
15

Using a crowbar, a person can remove a nail by exerting little force, whereas pulling directly on the nail requires a large forc

e to remove it (you probably can't). why?
Physics
1 answer:
algol [13]3 years ago
7 0
Here we deal with a lever law. It states that product of force and distance from a fixed point on a lever is equal on both sides.

F₁*d₁ = F₂*d₂

By analysing this formula we can see that applying small force on a great length equals great force on a small length.
To remove nail we need to apply certain force. If we use F₁ for this required force we can see that on other side we need to apply certain force. If we have greater arm length we need smaller force. In a crowbar arm length along which we apply force is greater than length of our arm. This leads to a conclusion that we need smaller force when using crowbar. Depending on the length of a nail it is possible that we need to apply force that is greater than force required to remove nail.
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11. A seesaw sits in static equilibrium. A child with a mass of 30 kg sits 1 m away from a pivot point. Another child sits 0.75
lora16 [44]

Answer:

<h2>40 kg</h2>

Explanation:

Find the diagram relating to the question for proper explanation of the question below.

Using the principle of moment

Sum of clockwise moments = Sum of anticlockwise moments

Moment = Force * perpendicular distance

For anti-clockwise moment:

Since the 30 kg moves in the anticlockwise direction according to the diagram

ACW moment = 30 * 1 = 30 kgm

For clockwise moment

If another child sits 0.75 m away from the pivot point on the opposite side, moment of the child in clockwise direction = M * 0.75 = 0.75M (M is the mass of the unknown child).

Equating both moments we have;

0.75M = 30

M = 30/0.75

M = 40 kg

The second child's mass is 40 kg

5 0
3 years ago
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Andrei [34K]

Answer:

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Explanation:

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7 0
2 years ago
A solar panel measures 0.57 m by 1.3 m. In direct sunlight, the panel delivers 6.6 A at 6 V. If the intensity of sunlight is 300
zheka24 [161]

Answer:

efficiency of solar panel is 18%

Explanation:

Energy received by the sunlight is given as

Power = intensity \times area

here we know the dimensions of the plate as

L = 0.57 m

W = 1.3 m

now we have

Area = (0.57)(1.3) m^2

A = 0.741 m^2

now the power received by the sun light is given as

P_1 = 0.741(300) = 222.3 W

now the output power due to solar panel is given as

P_{out} = V i

P_{out} = (6.6 A)(6 V)

P_{out} = 39.6 Watt

now the efficiency is given as

\eta = \frac{P_{out}}{P_{in}}

\eta = \frac{39.6}{222.3}

\eta = 0.18

8 0
4 years ago
What type of stimulus do we tend to be particularly aware of ?
Volgvan
Emotional stimuli is the answer to your question.
7 0
3 years ago
Find the potential energy of a 40kg cart that is on a hill that is 10 meters high
Vilka [71]

Explanation:

P.E. = mgh

PE = 40 × 10 × 10

PE = 4000 Joule

3 0
2 years ago
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