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Molality is the number of moles of solutes in 1 kg of solvent.
the molality of solution to be prepared is 2.0 molal.
therefore 2 moles in 1 kg water.
the mass of Li₂S required is - 46 g/mol x 2.0 mol = 92 g
the mass in 1 kg of solvent is - 92 g
Therefore mass of Li₂S required in 1600.0 g is - 92 g/kg x 1.6 kg = 147.2 g
Answer:
Explanation:
A) Formal charges represent an actual separation of charges.(FALSE)
(B) ΔHo rxn can be estimated from the bond enthalpies of reactants and products.(TRUE)
C)All second-period elements obey the octet rule in their compounds(FALSE).
(D)The resonance structures of a molecule can be separated from one another in the laboratory.(FALSE)
Bond enthalpy which is also reffered to as bond energy is the amount of energy that is required to break one mole of a bond.
taking the single bond between Oxygen and Hydrogen into considerationthe bond energy between their single bond is 463 kJ/mol.
formal charge is used for the comparison of the number of electrons present around an atom in a particular molecule with the number of electrons present around a neutral
Answer:
24382 J
162790 J
Explanation:
At 0°C, ice requires a certain amount of heat/energy to break its certain bonds and change its state into liquid water. This amount of heat per gram of ice is known as the latent heat of fusion of ice. And this heat is already detrmined and is equal to 334 J/g. Similarly, For water to convert into vapor at 100°C, it requires a certain amount of heat/energy to break its certain bonds and change its state into gas/vapor. This amount of heat per gram of water is known as the latent heat of vaporization of water, and it is equal to 2230 J/g.
Now, for one gram ice, 334 J heat is required for melting, hence for 73g of ice, 73x334 = 24382 J of heat is required.
Now, for one gram water, 2230 J heat is required for melting, hence for 73g of water, 73x2230 = 162790 J of heat is required.
Answer:
I would expect to extract the acetic acid.
Explanation:
In the first step, since we are adding a concentrated acid,<u> it will react with the bases present in the mixture (diethylamine and ammonia) </u><u>forming salts</u><u>, </u><u>which are soluble in water</u>. Therefore, after draining the aqueous layer, we will have phenol and acetic acid left in the organic layer.
In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.
