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JulijaS [17]
3 years ago
7

To separate liquids in a mixture of different liquids, each having different boiling points, one would use the separation techni

que of:
filtration

evaporation

distillation

chromatography
Chemistry
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer;

-Distillation

Explanation;

Distillation is a  technique that can be used to physically separate most homogeneous mixtures based on the difference in the boiling points of the substances involved.

A good example;  A flask hold liquids A, B, and C in a homogeneous mixture. The boiling points of A, B, and C are 130 C, 65 C, and 71 C, respectively. The flask is heated to 65C until all of liquid B is filtered out. The remaining mixture is heated to 71C until all of liquid C is filtered out, and only liquid A is left in the flask.

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Determine the number of moles of gas contained in a 1.25 L container at 25 degrees Celsius and 800 torr
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You would have to use the ideal gas law: PV = nRT where,

P = pressure
V = volume
n = moles
R = universal gas constant for a specific pressure (in this case it's 62.364 torr)
T = temperature in Kelvin

First, convert Celsius to kelvin by adding 273 to 25, which gives you 298K

Now plug in your variables to find n:

(800 torr)(1.25 L) = n(62.364)(298K)

1000 = 18584.472n

Now divide 1000 by 18584.472 to get n:

1000/18584.472 = 0.054 moles
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So the correct answer is e)
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At what height the acceleration due to gravity of the earth become half ?​
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Use the ΔHrxn values of the following reactions: 2SO2(g) + O2(g) → 2SO3(g) ΔHrxn = –196 kJ 2S(s) + 3O2(g) → 2SO3(g) ΔHrxn = –790
sesenic [268]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -297 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

S(s)+O_2(g)\rightarrow SO_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)    \Delta H_1=-196kJ

(2) 2S(g)+3O_2(g)\rightarrow 2SO_3(g)     \Delta H_2=-790kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=\frac{[1\times (-\Delta H_1)]+[1\times \Delta H_2]}{2}

Putting values in above equation, we get:

\Delta H^o_{rxn}=\frac{[(1\times -(-196))+(1\times (-790))}{2}=-297kJ

Hence, the \Delta H^o_{rxn} for the reaction is -297 kJ.

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