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2 years ago

How many sodium atoms in sodium sulfate.

Chemistry

1 answer:

Annette [7]2 years ago

5 0

Answer:

Explanation:

Na2 SO4 is the chemical identity. You can count the number of atoms just by looking

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2Ag (s) + H2S(s) → Ag2S(s) + H2(g)

Advocard [28]

Answer: Oxidation half: $2Ag\rightarrow 2Ag^++2e^-$

Reduction half: $2H^++2e^-\rightarrow H_2$

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

$2Ag(s)+H_2S(s)\rightarrow Ag_2S(s)+H_2(g)$

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Oxidation half: $2Ag\rightarrow 2Ag^++2e^-$

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Reduction half: $2H^++2e^-\rightarrow H_2$

8 0

2 years ago

Please please please help me ill give brainliest

Mnenie [13.5K]

Answer: the answer is A.

8 0

3 years ago

How many moles of carbon (C) are there in 92.5 g of C?

aksik [14]

Answer:

c are there 93.5 of c yan siguro

8 0

2 years ago

onvert the value of Kc to a value of Kp for the following reaction: N2(g)+3H2(g)⇌2NH3(g) Kc = 0.50 at 400 °C.

ale4655 [162]

Answer:

$K_p= 0.00016$

Explanation:

The relation between Kp and Kc is given below:

$K_p= K_c\times (RT)^{\Delta n}$

Where,

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

$N_2_{(g)}+3H_2_{(g)}\rightleftharpoons2NH_3_{(g)}$

Given: Kc = 0.50

Temperature = $400^oC=[400+273]K=673K$

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(3+1) = -2

Thus, Kp is:

$K_p= 0.50\times (0.082057\times 673)^{-2}$

$K_p= 0.00016$

6 0

3 years ago

The ΔHsoln is _____.

nydimaria [60]

Sometimes negative sometimes positive, your answer is B!

4 0

3 years ago