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Ivanshal [37]
3 years ago
7

The solid XY decomposes into gaseous X and Y: XY(s) m X(g) + Y(g) Kp = 4.1 (at 0 °C) If the reaction is carried out in a 22.4 L

container, which initial amounts of X and Y will result in the formation of solid XY?a) 5 mol X; 0.5 mol Yb) 2.0 mol X; 2.0 mol Yc) 1 mol X; 1 mol Yd) none of the above

Chemistry
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

None of the conditions will favor either the forward reaction or backward reaction , hence the answer is D

Explanation:

  • The principle of chemical Equilibrium is applied here, where the concentration of the reactants or the forward reaction is same as the concentration of the products or the backward reaction.

  • The equilibrium constants is also involved here, K can be in terms of pressure (Kp) or concentration (Kc) hence equilibrium constant is the ration of the concentration of the products to the concentration of the reactants raised to the power of the coefficient of the reactants and products.
  • Partial pressure , total pressure and the mole fraction relationship is also applied
  • The step by step explanation is as shown in the attachment below.

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Explanation:

Given that:

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The reaction for the decomposition:

Mg(HCO3)2 (s) ⇒ CO2 (g) + H2O (g) + MgCO2 (s)

It says that 1 mole of Mg(HCO3)2  yielded 1 mole of  MgCO2  on decomposition

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putting the values in the equation:

percent yield = \frac{1.071}{68.31}

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