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Ivanshal [37]
3 years ago
7

The solid XY decomposes into gaseous X and Y: XY(s) m X(g) + Y(g) Kp = 4.1 (at 0 °C) If the reaction is carried out in a 22.4 L

container, which initial amounts of X and Y will result in the formation of solid XY?a) 5 mol X; 0.5 mol Yb) 2.0 mol X; 2.0 mol Yc) 1 mol X; 1 mol Yd) none of the above

Chemistry
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

None of the conditions will favor either the forward reaction or backward reaction , hence the answer is D

Explanation:

  • The principle of chemical Equilibrium is applied here, where the concentration of the reactants or the forward reaction is same as the concentration of the products or the backward reaction.

  • The equilibrium constants is also involved here, K can be in terms of pressure (Kp) or concentration (Kc) hence equilibrium constant is the ration of the concentration of the products to the concentration of the reactants raised to the power of the coefficient of the reactants and products.
  • Partial pressure , total pressure and the mole fraction relationship is also applied
  • The step by step explanation is as shown in the attachment below.

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5 0
3 years ago
Jason measures three values of density for his unknown. The values he obtains are: 1.019 g/mL 1.498 g/mL 1.572 g/mL What is the
jok3333 [9.3K]

<u>Answer:</u> The average of the densities of the given measurements is 1.363 g/mL

<u>Explanation:</u>

The equation used to calculate density of a substance is given by:

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

We are given:

First measured value of density, d_1 = 1.019 g/mL

Second measured value of density, d_2 = 1.498 g/mL

Third measured value of density, d_3 = 1.572 g/mL

Putting values in above equation, we get:

\rho_{mix}=\frac{d_1+d_2+d_3}{3}

\rho=\frac{1.019+1.498+1.572}{3}\\\\\rho=1.363g/mL

Hence, the average of the densities of the given measurements is 1.363 g/mL

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3 years ago
How do the lengths of day contrast for the summer solstice and winter solstice?
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Question 3 0
Tanya [424]

Answer:

Option D. KBr < KCl < NaCl

Explanation:

We'll begin by calculating the number of mole of each sample.

This can be obtained as follow:

For NaCl:

Mass = 1 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 1/58.5

Mole of NaCl = 0.0171 mole

For Kbr:

Mass = 1 g

Molar mass of KBr = 39 + 80 = 119 g/mol

Mole of KBr =?

Mole = mass /Molar mass

Mole of KBr = 1/119

Mole of KBr = 0.0084 mole

For KCl:

Mass = 1 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1/74.5

Mole of KCl = 0.0134 mole

Summary

Sample >>>>>>>> Number of mole

NaCl >>>>>>>>>> 0.0171

KBr >>>>>>>>>>> 0.0084

KCl >>>>>>>>>>> 0.0134

Arranging the number of mole of the sampl in increasing order, we have:

KBr < KCl < NaCl

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