Both HF and HBr experience H-bond, dipole, and dispersion forces. These forces allow the compounds to have stronger bonds with each other. HF would experience a higher amount of attraction between its molecules. This is because fluorine is more electronegative than bromine.
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Answer No 1:
The chemical model that is flawed is:
4 C2 + S8 → 4 CS2
In this reaction, there are more number of carbon atoms in the reactants but lesser number of cabon atoms in the products. For a reaction to be balanced, there should be the same number of atoms in the reactants and products. Hence, option A does not represent a balanced equation.
<em>Answer No 2:</em>
The correct option is B) The model shows an unbalanced number of carbon atoms.
Consider the equation:
4 C2 + S8 → 4 CS2
In the reactants side of the equation, there are 8 atoms of carbon. In the products side there are only four carbon atoms. This shows that this equation in not balanced because of the carbon atoms.
The number of sulfur atoms remains same before the reaction and after the reaction. There are eight sulfur atoms in the reactants as well as products.
Hydrogen i think. the orbital of hydrogen is peculiar
Answer:
it should be 310.18 g/mol :)
Answer:
Both <u>elements </u>and <u>compounds</u> can be classifies as pure substances because they have distinct properties and composition.
Explanation:
Elements and compounds are considered as pure substances because both are always formed form are have same kind of atoms.
For example,
Carbon dioxide is compound. It always consist of one carbon atom and two oxygen atoms.
Water is compound it always have same kind of atoms two hydrogen and one oxygen that's why compounds are considered as pure substances.
Same is the case with elements. For example,
Hydrogen is element and it always consist of H atoms.
Iron is another element and it always have iron atoms.
So elements and compounds are always consist of same substances that's why they are considered as pure.
