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Tanya [424]
3 years ago
15

What is the sequence of energy transformations associated with a hydroelectric dam?

Physics
2 answers:
Hatshy [7]3 years ago
3 0

Gravitational potential energy -> Kinetic energy -> Mechanical energy -> Electrical energy.

The water starts up (potential) and flows down (kinetic), the flowing water turns a big wheel (mechanical) which creates electricity (electrical).

alexdok [17]3 years ago
3 0

Answer:

gravitational potential energy into kinetic energy into mechanical energy into electrical energy

Explanation:

Hydroelectric dam is used to convert gravitational potential energy stored in water to electrical energy. The water is stored at a height. As the water is releases, the gravitational potential energy converts to kinetic energy. The water is allowed to strike the turbine which starts rotating. Thus, kinetic energy is converted to mechanical energy. The turbine is connected to generator where mechanical energy is converted to electrical energy.

Thus, the correct sequence of energy transformation is: gravitational potential energy into kinetic energy into mechanical energy into electrical energy

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A ball is thrown straight up with a speed of 30

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3 years ago
Convert <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%280.779mg%29%28min%29%7D%7BL%7D" id="TexFormula1" title="\frac{(0.779mg)(mi
Orlov [11]

The number converted is 0.0467 \frac{(kg)(s)}{m^3}

Explanation:

In order to convert from the original units to the final units, we have to keep in mind the following conversion factors:

1 kg = 1000 g = 10^6 mg

1 min = 60 s

1 m^3 = 1000 L

The original unit that we have is

\frac{mg\cdot min}{L}

Therefore, it can be rewritten as:

=\frac{mg \frac{1}{10^6 mg/kg}\cdot min\cdot  60 s/min}{L\frac{1}{1000L/m^3}}=0.06 \frac{(kg)(s)}{m^3}

Therefore, since the initial number was 0.779, the final value is

0.779\cdot 0.06 \frac{(kg)(s)}{m^3}=0.0467 \frac{(kg)(s)}{m^3}

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