Let's apply the principle of conservation of energy.
Heat of metal = Heat of water
mCmetalΔT = mCwaterΔT
Applying the given values,
(45 g)(Cmetal)(100 - 28 °C) = (130 g)(4.18 J/g-°C)(28 - 25 °C)
Solving for Cmetal,
<em>Cmetal = 0.503 J/g°C
Therefore, the heat capacity of the unknown metal is 0.503 J/g</em>°C.
Answer:
113.80 mL
Explanation:
Given that:
Volume 
Temperature

Pressure 
At standard temperature and pressure;
Temperature 
Pressure
= 760 mmHg
Using the formula for a combined gas law:




Chemical waste from factories
Answer:
Cell
Explanation:
I just passed this unit a month ago.
Answer:
14-6
8
so 8 is the answer because atomic number is number of protons and atomic mass is sum of protons and neutrons so to find the number of neutrons we will subtract proton number with the atomic mass.
Thanks