The chemical formula for ammonium oxalate is C2H8N2O4
This is a combustion reaction.
2C6H6 + 9O2➡️ 6CO2 + 6H2O
<span>Kr has 8 valence electrons plus 1 for each Kr-F single bond. Total = 10 elcetrons
</span>
Answer: In the three-dimensional structure of methane, CH₄, the hydrogen atoms attached to a carbon atom are aligned <span>
<u>at the corners of a Tetrahedron</u>.
Explanation: In
Methane (CH</span>₄) the central atom (carbon) is bonded to four hydrogen atoms. So, the central atom is having four electron pairs and all pairs are bonding pairs and lacks any lone pair of electron. According to
Valence Shell Electron Pair Repulsion (VSEPR) Theory the central atom with
four bonding pair electrons and
zero lone pair electrons will attain a
tetrahedral geometry with
bond angles of 109°. Hence, the shape of CH₄ is tetrahedral.
Answer: Molecular formula will be 
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C= 40 g
Mass of H = 6.71 g
Mass of O = 100 - (40+6.71 ) = 53.29 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of H =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = 
For H =
For O = 
The ratio of C: H: O= 1 : 2: 1
Hence the empirical formula is 
The empirical weight of
= 1(12)+2(1)+1(16)= 30g.
The molecular weight = 90.08 g/mole
Now we have to calculate the molecular formula:

The molecular formula will be=
Molecular formula will be 