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2 years ago

Find all complex solutions of 2x^2+3x+5=0 using the quadratic equation.

1 answer:

katrin2010 [14]2 years ago

7 0

2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
x = -(3 / 4) + sq root (-36) / 4
x = -(3 / 4) - sq root (-36) / 4

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Answer:

2/5 < 5/8 < 6/7 < 1

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Step-by-step explanation:

It is required to compare Two-fifths, Six-sevenths, Five-eighths, and 1

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The easy method is convert the rational numbers to decimal numbers

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2/5 , 5/8 , 6/7 , 1

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