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attashe74 [19]
3 years ago
11

Find all complex solutions of 2x^2+3x+5=0 using the quadratic equation.

Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0
<span>2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
</span><span>x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
</span><span>x = -(3 / 4) + sq root (-36) / 4
</span><span>x = -(3 / 4) - sq root (-36) / 4

</span>
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