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attashe74 [19]
3 years ago
11

Find all complex solutions of 2x^2+3x+5=0 using the quadratic equation.

Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0
<span>2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
</span><span>x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
</span><span>x = -(3 / 4) + sq root (-36) / 4
</span><span>x = -(3 / 4) - sq root (-36) / 4

</span>
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Solve.
Nat2105 [25]

The solution to the algebraic equation, −0.4x − 3.1 = 5.9, is:<u> x = -22.5</u>

Given the algebraic equation, −0.4x−3.1 = 5.9, to solve for x, follow the steps below:

−0.4x − 3.1 = 5.9

  • Add 3.1 to both sides

−0.4x − 3.1 + 3.1 = 5.9 + 3.1

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  • Divide both sides by -0.4

-0.4x/-0.4 = 9/-0.4

x = -22.5

Therefore, the solution to the algebraic equation, −0.4x − 3.1 = 5.9, is:<u> x = -22.5</u>

<u></u>

<u></u>

Learn more here:

brainly.com/question/16864747

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