<u><em>Kinetic Energy Pulls Any object to the ground.This Energy is a part of Gravity.</em></u>
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The voltage in the resistor is 63 V
Explanation:
We can solve the problem by applying Ohm's law, which states the relationship between voltage, current and resistance in a resistor:

where
V is the voltage
R is the resistance
I is the current
For the resistor in this problem, we have:
I = 0.42 A is the current
is the resistance
Substituting into the equation, we find the voltage needed:

Learn more about voltage and current:
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Answer:
when volume and the number of particles are constant
Explanation:
Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Gay Lussac's law is given by;

The ideal gas law is the equation PV = nRT
Where;
P is the pressure.
V is the volume.
n is the number of moles of substance.
R is the ideal gas constant.
T is the temperature.
Generally, raising the temperature of an ideal gas would increase its pressure when volume and the number of particles are constant.
This ultimately implies that, when volume and the number of particles are held constant, there would be a linear relationship between the temperature and pressure of a gas i.e temperature would be directly proportional to the pressure of the gas. Thus, an increase in the temperature of the gas would cause an increase in the pressure of the gas at constant volume and number of particles.
We have to assume that the truck was not moving
before he started pushing it.
After he did 12 J of work pushing it, the truck had
12 J of kinetic energy.
Kinetic energy = (1/2) (mass) (speed²)
12 J = (1/2) (3 kg) (speed²)
Divide each side by 1.5 kg : 12J / 1.5 kg = speed²
1 J = 1 newton-meter (12 kg-m²/sec²) / (1.5 kg) = speed²
= 1 kg-m² / sec²
(12 / 1.5) ( m²/sec²) = speed²
Speed = √(8 m²/s²)
Speed = 2.83 m/s .
We can't say anything about velocity, because we don't know
anything about the direction in which the truck is moving.
The speed of a wave depends on the medium :)