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ivann1987 [24]
3 years ago
7

What is the name of the particle that compounds are made of?

Physics
1 answer:
VashaNatasha [74]3 years ago
8 0

Answer:

Explanation:

atoms

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A ski lift is used to transport people from the base of a hill to the top. If the lift leaves the
Liono4ka [1.6K]
The energy of the ski lift at the base is kinetic energy:
K= \frac{1}{2}mv^2
where m is the mass of the ski lift+the people carried, and v=15.5 m/s is velocity at the base.
As long as the ski lift goes upward, its velocity decreases and its kinetic energy converts into potential energy. Eventually, when it reaches the top, its final velocity is v=0, so no kinetic energy is left and it has all converted into gravitational potential energy, which is 
U=mgh
where g=9.81 m/s^2 and h is the height at the top of the hill.

So, since the total energy must conserve, we have
U=K
and so
mgh =  \frac{1}{2}mv^2
from which we find the height:
h= \frac{v^2}{2g}= \frac{(15.5m/s)^2}{2\cdot 9.81 m/s^2}=12 m
8 0
3 years ago
As blood passes through the capillary bed in an organ, the capillaries join to form venules (small veins). If the blood speed in
Semenov [28]

Answer:

A_2 = 2.5\ cm^2

Explanation:

given,

velocity factor = 4

Cross-sectional area of venules(A₁) = 10 cm²

cross sectional area of capillaries(A_2) = ?

continuity equation = Q = AV

now,

\dfrac{A_1}{A_2} = \dfrac{V_2}{V_1}

\dfrac{10}{A_2} =4

\dfrac{10}{4} =A_2

A_2 = 2.5\ cm^2

hence, the area of capillaries is equal to 2.5 cm₂

4 0
3 years ago
Which statement best compares an asteroid with Earth?
IgorLugansk [536]

Answer:C) Both have rocky composition

6 0
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Where can classic examples of shield volcanoes be found?
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3 years ago
A plane wave with a wavelength of 500 nm is incident normally ona single slit with a width of 5.0 × 10–6 m.Consider waves that r
kaheart [24]

To solve this exercise it is necessary to use the concepts related to Difference in Phase.

The Difference in phase is given by

\Phi = \frac{2\pi \delta}{\lambda}

Where

\delta = Horizontal distance between two points

\lambda = Wavelength

From our values we have,

\lambda = 500nm = 5*10^{-6}m

\theta = 1\°

The horizontal distance between this two points would be given for

\delta = dsin\theta

Therefore using the equation we have

\Phi = \frac{2\pi \delta}{\lambda}

\Phi = \frac{2\pi(dsin\theta)}{\lambda}

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\Phi= 1.096 rad \approx = 1.1 rad

Therefore the correct answer is C.

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3 years ago
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