Answer:
Forces Due to Friction and Newton's Third Law
The forces on the cart include the forward force the horse exerts on the cart and the backward force due to friction at the ground, acting on the wheels. At rest, or at constant velocity, these two are equal in size, because the acceleration of the cart is zero.
Answer:
the point between Earth and the Moon where the gravitational pulls of Earth and Moon are equal is <em>E)3.45 × 10⁸ m</em>
Explanation:
The force that the Earth exerts on a mass m is
F_e = (G M_e m) / R_e²
where
- G is the universal gravitational constant
- M_e is the mass of Earth
- R_e is the radius of Earth
The force that the Moon exerts on a mass m is
F_m = (G M_m m) / R_m²
where
- G is the universal gravitational constant
- M_m is the mass of the Moon
- R_m is the radius of the Moon
Therefore, the point where the gravitational pulls of Earth and Moon are equal is:
F_e = F_m
R_e + R_m = R = 3.84×10⁸ m
Thus,
(G M_e m) / R_e² = (G M_m m) / R_m²
M_e / R_e² = M_m / (R - R_e²)
(R - R_e²) / R_e² = M_m / M_e
(R - R_e) / R_e = (M_m / M_e)^1/2
R_e(R/R_e -1) / R_e = (M_m / M_e)^1/2
R/ R_e = (M_m / M_e)^1/2 + 1
R_e = R / [(M_m / M_e)^1/2 + 1]
R_e = (3.84×10⁸ m) / [(7.35 x 10²² kg / 5.97 x 10²⁴ kg )^1/2 + 1]
R_e = 3.45 × 10⁸ m
Therefore, the point between Earth and the Moon where the gravitational pulls of Earth and Moon are equal is <em>3.45 × 10⁸ m.</em>
Answer:
Static friction is what keeps the box from moving without being pushed, and it must be overcome with a sufficient opposing force before the box will move. Kinetic friction (also referred to as dynamic friction) is the force that resists the relative movement of the surfaces once they're in motion. Hence why they can be distinguished. Have a good day
Answer:
Explanation:
Given that,
Initial speed of a car, u = 13 m/s
Final speed of a car, v = 25 m/s
Time, t = 5 s
We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :
So, the acceleration of the car is 
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