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3 years ago

The warm rising air moves toward the land where it cools and?

Physics

2 answers:

pashok25 [27]3 years ago

8 0

Well that's is really important because well you know because we can't just have summer every single month right?

slega [8]3 years ago

5 0

And the cold air moves up wards where it heatens

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The drawing shows a person (weight W = 588 N, L1 = 0.838 m, L2 = 0.398 m) doing push-ups. Find the normal force exerted by the f

zhenek [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Force on each hand is 196.22 N

Force on each foot is 95.8 N

Explanation:

In order to get a better understanding of this question let us explain some concepts

Normal Force:

We can define normal force Fn as that type of force which makes a 90 degree angle with the surface on which it is exerted.

Torque:

We can define torque as the moment of forces that tends to produce or cause rotation

From the question we are given that

Weight of body is (W) = 584 N

The normal force on both hands (Ha) = ?

The normal force on both legs (Lg) = ?

Looking at the diagram the person is at equilibrium so

584 = Ha + Lg

an also this mean that torques acting on the body is balanced

So, 0.410 Ha = 0.840 Lg

Making Lg the subject of formula in the equation above we

Lg = 0.4881 Ha

Considering the first equation and replacing Lg with this recent equation we have

584 = Ha + 0.4881 Ha

Therefore Ha = 392.44 N

This value obtained is for both hands for each hand we divide by 2

Therefore we have for each hand $= 392.44/2$ =196.55 N

Since we have been able to get the force on both hands we can substitute it in to the equation where we made Lg the subject of formula and we have

Lg = 0.4881 × 392.44

= 191.22 N

The value above is the force on both legs to obtain the force on each leg we have

191.22/2 = 95.8 N.

8 0

4 years ago

A 2.5-m-long tension member (E = 70 GPa) has cross-sectional dimensions of 25 mm x 35 mm. Determine the maximum load P that may

Alja [10]

Answer:

Force = 7.3 kN

Explanation:

Elastic Modulus = Stress / Strain

Since the maximum stress applied can be 90 MPa, lets check the corresponding maximum strain using the above equation.

70 * 10^9 = 90 * 10^6 / Strain

Strain = 0.0012857

Strain = Change in length/total length

Change in Length = 0.0012857 * 2.5

Change in Length = 0.003214 m

Converted to mm this is: 0.003214 * 1000 = 3.214 mm

Thus we can see that strain is the limiting factor, and not stress. This is because with the maximum stress possible applied, we go over the strain limit.

Doing another quick calculation, we can take out the maximum stress with strain equal to 3mm/2.5m

Strain = (3/1000)/2.5

Strain = 0.0012

Modulus of elasticity = Stress/ Strain

Stress = 70 * 10^9 * 0.0012

Stress = 84 MPa

This stress is under both the strain and stress limit.

Taking out the force due to this stress:

Stress = force / area

Force = 84 * 10^6 * Area

Force = 84 * 10^6 * (25/1000) * (35/1000)

Force = 7350 N or 7.3 kN

8 0

3 years ago

Which statement correctly describes the relationship between frequency and wavelength?

liraira [26]

For a wave:

v = fλ

v is the velocity, f is the frequency, and λ is the wavelength.

Assuming the velocity of the wave doesn't change...

If you increase its frequency, its wavelength will shorten.

5 0

4 years ago

Read 2 more answers

If you had a planet to choose from to live in what would it be?

postnew [5]

I personally would live on Mars cuz that is red cuz

4 0

3 years ago

Read 2 more answers

Ann is driving a motorboat across a river that is 2 km wide. The boat has a speed of 20 km/h in still water, and the current in

elena-14-01-66 [18.8K]

Answer:

Explanation:

The resultant velocity of the motorboat due to the current perpendicular to the motion of the boat can be calculated by drawing a triangle to represent this motion. The velocity of the motorboat is the base whereas the velocity of the river is the perpendicular of the triangle (picture attached).

The angle is $Tan^{-1}$ (perpendicular/base);

$Tan^{-1}$ (5/20)= 14.0;

The triangle can be enlarged such that the perpendicular now represents the width of the river and the perpendicular represents the distance between the dock and landing place.

The distance between dock and landing place is:

a) base*Tan(∅) = 2*Tan(14) = 0.5km

b Time = 2/20= 0.1 hours. This is because the horizontal component of the motion due to velocity of motor boat will be considered for horizontal distance of 2 km.

6 0

4 years ago