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victus00 [196]
4 years ago
5

A raft of 180 kg carries two swimmers with masses of 50 kg and 80 kg. The raft is initially floating at rest. The two swimmers s

imultaneously dive off opposite ends of the raft, each would a horizontal velocity of 3 m/s. With what velocity and in what direction does the raft start to move?
Physics
1 answer:
nirvana33 [79]4 years ago
8 0

Answer:

v=0.5m/s

Explanation:

Given a raft of 180kg, and two simmers of 50kg and 80kg:

The two rafts have an initial velocity of zero:

\bigtriangleup P_{raft}+\bigtriangleup  P_{50}+\bigtriangleup  P_{80}=0\\\\m_R\bigtriangleup  v_R+m_{50}\bigtriangleup  v_{50}+m_{80}\bigtriangleup  v_{80}=0\\\\m_R\bigtriangleup  v_R=-m_{50}\bigtriangleup  v_{50}-m_{80}\bigtriangleup  v_{80}\\\\\bigtriangleup v_R=\frac{-m_{50}\bigtriangleup  v_{50}-m_{80}\bigtriangleup  v_{80}}{m_R}\\\\\bigtriangleup v_R=\frac{-(50kg\times3m/s+80kg\times-3m/s)}{180kg}\\\\\bigtriangleup v_R=0.5m/s

Hence, the raft starts moving with avelocity of 0.5m/s

-The raft will continue moving in the direction it was initially moving. The raft has a larger mass than the combined mass of the two swimmers, by law of momentum conservation, it's change in velocity will be negligible.

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LUCKY_DIMON [66]

Hi there!

We can use the work-energy theorem to solve.

Recall that:

\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}

The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:

W = \frac{1}{2}(50)(5.61^2) = 786.8025 J

Now, we can define work:

\large\boxed{W = Fdcos\theta}}

Now, plug in the values:

786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta

Solve for theta:

cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}

4 0
3 years ago
Your job is to lift 30 kgkg crates a vertical distance of 0.90 mm from the ground onto the bed of a truck. For related problem-s
Gekata [30.6K]

Answer:

The number of crates is 84580.

Explanation:

mass, m = 30 kg

height, h = 0.9 mm  

Power, P = 0.5 hp = 0.5 x 746 W = 373 W

time, t = 1 minute = 60 s

Let the number of crates is n.

Power is given by the rate of doing work.

P = \frac{n m gh}{t}\\\373 =\frac{n\times 30\times9.8\times 0.9\times 10^{-3}}{60}\\\\n =84580

7 0
3 years ago
The best way to study young stars hidden behind interstellar dust clouds would be to use
Ainat [17]

Answer: Infrared light

Explanation:

Infrared light is an electromagnetic radiation which has longer wavelength than visible light.

cool and faint objects are difficult to be detected using visible light.

Infrared light can pass through dust and clouds of gases. Thus, it is the best way to study the young stars hidden behind interstellar dust clouds.

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3 years ago
Amir and Gracie left some evidence of breakfast behind. Luckily, some of it can be changed back. What does Mosa write down as cl
marta [7]

Answer:

You could say that it was not a chemicly change because that is when you say this is just a example that if you cook eggs you cant un-cook them

Explanation:

3 0
3 years ago
An 80-kg hiker climbs to the top of a tall hill and builds up 470,000 J of gravitational potential energy. How high did the hike
nekit [7.7K]

Answer:

599 meters is the answer rounded to the nearest whole number and 599.489795918 meters is the complete answer

Explanation:

to find gravitational potential energy you multiply mass x acceleration due to gravity (always 9.8 on earth) x hight

since we know the gravitational potential energy and want to find out the hight, we take the gravitational potential energy (470,000) and divide it by the product of acceleration due to gravity x mass (9.8 x 80)

so how high the hiker climbed is equal to 470,000 divided by (9.8 x 80)

hight = 470,000 / (9.8 x 80)

hight = 470,000 / 784

hight = 599.489795918 meters

as for rounding, if the decimal is less than 5 you round "down" and keep the current whole number, if the decimal is 5 or greater you round "up" and add 1 to get your new number

5 0
3 years ago
Read 2 more answers
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