Your job is to lift 30 kgkg crates a vertical distance of 0.90 mm from the ground onto the bed of a truck. For related problem-s
1 answer:
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The acceleration of the rocket will be "56.2 m/s²".
According to the question,
The initial speed during launch,
- u = 0 m/s
The speed at fuel running out point,
= 375 m/s
Height,
- h = 1.25 km
= 1250 m
As we know,
→
or,
→
By putting the values, we get
→
→
→
Thus the above solution is correct.
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Ok, a couple of things have to be accounted for here. First, since the block is moving relative to the wall we have to use the kinetic coefficient of friction, 0.40. The second consideration is that since the block is moving at a constant velocity, the acceleration is zero. This means, by Newton's second Law, that the net force is zero. So the force of gravity must be equal to the friction force of the wall resisting its fall. This friction force is the product of the normal force (which we are seeking) and the kinetic coefficient of friction. We can then set these two forces equal:
