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2 years ago

Problema 1. Un Clavadista se lanza desde un trampolín a diferentes alturas 10 m, 3 m, y 1 m, Calcular:

Physics

1 answer:

Salsk061 [2.6K]2 years ago

4 0

La velocidad del buzo es de 7.04 m/s, 8.84 m/s y 2.27 m/s respectivamente.

<h3 /><h3>Velocidad </h3>

La velocidad es la relación entre la distancia total recorrida y el tiempo total empleado. Está dado por:

Velocidad = distancia/tiempo

Para 10m de altura:

Velocidad = 10 m/1.42 s = 7.04 m/s

Para 3m de altura:

Velocidad = 3 m/0.78 s = 3.84 m/s

Para 1m de altura:

Velocidad = 1 m/0.44 s = 2.27 m/s

La velocidad del buzo es de 7.04 m/s, 8.84 m/s y 2.27 m/s respectivamente.

Obtenga más información sobre la velocidad en: brainly.com/question/4931057

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How physical science can be truth?

JulsSmile [24]

Because it is physically true day really know that by just knowing it very well

4 0

2 years ago

A ship sets sail from Rotterdam, The Netherlands, heading due north at 8.00 m/s relative to the water. The local ocean current i

Nuetrik [128]

Answer:

The velocity of the ship relative to the earth V = 9.05 $\frac{m}{s}$

Explanation:

The local ocean current is = 1.52 m/s

Direction $\theta$ = 40°

Velocity component in X - direction $V_{x}$ = 1.52 $\cos 40$ °

$V_{x}$ = 1.164 $\frac{m}{s}$

Velocity component in Y - direction $V_{y}$ = 8 + 1.52 $\sin 40$ °

$V_{y}$ = 8.97 $\frac{m}{s}$

The velocity of the ship relative to the earth

$V = \sqrt{V_{x}^{2} + V_{y} ^{2} }$

Put the values of $V_{x}$ and $V_{y}$ we get,

⇒ $V = \sqrt{1.164^{2} + 8.97 ^{2} }$

⇒ V = 9.05 $\frac{m}{s}$

This is the velocity of the ship relative to the earth.

7 0

3 years ago

at the center of the neutral metal block, what is the direction of the electric field contributed by the charge in and on the me

elena-14-01-66 [18.8K]

The direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.

<h3>How to determine electric field direction in a metal block?</h3>

The charge always remain on outer surface of metal and inside the metal block, the net electric field is zero. But due to dipole there is an electric field at the center of metal block i.e. at point R along direction line 1.

Now, to make make the net electric field zero at center, the electric field by the charge in and on the metal block must be equal in magnitude to that of electric field due to dipole at point R and in opposite direction to that of the net electric field at at R due to dipole.

The electric field by the charge in and on the metal block will be making 180° angle to the electric field due to dipole at point R.

Hence the direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.

To know more about electric field, click on brainly.com/question/11509296

#SPJ4

4 0

8 months ago

The movement of water is like the flow of the electricity. Electricity must have a complete path for the flow. This movement is

Mama L [17]

The answer is current.

Current in the context of an electrical circuit is the flow of charge. Current is a quantity that is physical and can be measured. Current is defined as the rate of the flow charge past a certain point in a circuit. Current is expressed in Amperes which is equal to 1 coulomb/1second.

7 0

2 years ago

The potential energy stored in the compressed spring of a dart gun, with a spring constant of 31.50 N/m, is 1.240 J. Find by how

Ber [7]

Answer:

0.281 m

Explanation:

Applying,

W = 0.5ke².................. Equation 1

Where W = Workdone by the stretched spring, k = spring constant, e = extension/ compression of the spring

make e the subject of the equation

e = √(2W/k)................ Equation 2

From the question,

Given: W = 1.240J, k = 31.50 N/m

Substitute these values into equation 2

e = √(2×1.240/31.50)

e = √(0.07873)

e = 0.281 m

8 0

3 years ago