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melisa1 [442]
3 years ago
11

Ill give 15 points to the one who helps me with this

Physics
1 answer:
alexandr402 [8]3 years ago
6 0
Machenical number one
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A crate is being pulled down an incline as shown in the figure. With respect to the crate's direction of motion, which of the fo
Dmitrij [34]

Answer: Fn

Explanation: Because Fn is applying force upward

7 0
3 years ago
We are able to see an object when it:
xenn [34]

Answer:

C. reflects one or more visible light frequencies.

Explanation:

The color that we see is the color that is deflected from the RGBHSB.etc. This means that the light has all the colors within, and the object it hits absorbs all but one color, in which it deflects for our eyes to see.

~

4 0
4 years ago
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What happens to the acceleration of an object if the net force that acts on it triples in magnitude?
poizon [28]

F=ma Force is equal to mass times acceleration.


So looking at the equation if mass stays the same but we make F three times larger then acceleration will become 3 times larger as well because the equation must remain equal on both sides.


just multiply both sides of the equation F=ma times 3. So 3xF=3x ma

5 0
4 years ago
An object, located 80.0 cm from a concave lens, forms an image 39.6 cm from the lens on the same side as the object. What is the
kramer

Answer:

-78.4 cm

Explanation:

We can solve the problem by using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

p is the distance of the object from the lens

q is the distance of the image from the lens

f is the focal length

Here we have

p = 80.0 cm

q = -39.6 cm (negative, because the image is on the same side as the object , so it is a virtual image)

Substituting, we find f:

\frac{1}{f}=\frac{1}{80.0 cm}+\frac{1}{-39.6 cm}=-0.0128 cm^{-1}

f=\frac{1}{0.0128 cm^{-1}}=-78.4 cm

5 0
4 years ago
PLEASE HELP!!
astraxan [27]

Answer:

Explanation:

\lambda\\ = v/f

^That is the formula we are going to use.

Now, we were given the speed (v), which is 20.

Now we need to find frequency, in order to solve for the wavelength.

Frequency is the amount of waves in a fixed unit of one second, meaning our F value is the value of 5 divided by 4.

5/4 = 1.25

Therefore our F is 1.25

Now lets plug it in

\lambda\\ = v/f

\lambda\\ = 20/1.25

\lambda\\ = 16

Conversion:

\lambda\\ = 8

3 0
3 years ago
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