100N describes the weight of the sandbag, while 100kg is the mass of the sandbag.
To calculate acceleration, divide your weight by the mass, thus the accleration is:
Answer:

Explanation:
Given that :
mass of the SUV is = 2140 kg
moment of inertia about G , i.e
= 875 kg.m²
We know from the conservation of angular momentum that:

![mv_1 *0.765 = [I+m(0.765^2+0.895^2)] \omega_2](https://tex.z-dn.net/?f=mv_1%20%2A0.765%20%3D%20%5BI%2Bm%280.765%5E2%2B0.895%5E2%29%5D%20%5Comega_2)
![2140v_1*0.765 = [875+2140(0.765^2+0.895^2)] \omega_2](https://tex.z-dn.net/?f=2140v_1%2A0.765%20%3D%20%5B875%2B2140%280.765%5E2%2B0.895%5E2%29%5D%20%5Comega_2)



From the conservation of energy as well;we have :

^2 -2140(9.81)[\sqrt{0.76^2+0.895^2} -0.765]] =0](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%20%5B875%2B2140%280.765%5E2%2B0.895%5E2%29%5D%280.4262%20%5C%20v_1%29%5E2%20-2140%289.81%29%5B%5Csqrt%7B0.76%5E2%2B0.895%5E2%7D%20-0.765%5D%5D%20%3D0)






Answer:
The answer is O C. A flower absorbs most of the light that hits it.
Explanation:
- <u><em> blackbody radiator is defined as an object that absorbs all electromagnetic radiation that falls on it at all frequencies over all angles of incidence.</em></u>
- <u><em> No radiation is reflected from such an object. According to thermodynamic arguments embodied in Kirchhoff's law, a good absorber is also a good emitter.</em></u>
<h3>Answer:</h3>
- 24.5 km/h
- 4 17/27 m/s
- 11/3 m/s²
<h3>Explanation:</h3>
1. The average speed is the ratio of total distance to total time:
... speed = distance/time = (92 km +55 km)/(3 h +3h) = (147 km)/(6 h)
... = 24.5 km/h
2. speed = distance/time = (125 m)/(27 s) = 4 17/27 m/s
3. a = ∆v/∆t = (15 m/s -4 m/s)/(3 s) = 11/3 m/s²
Proceed with caution before crossing