Ask question

Ask question

All categories

3 years ago

6

If a transverse wave of energy travels through the water in this pond ,how wil the floating leaf be moved

2 answers:

STatiana [176]3 years ago

8 0

Move up and down but stay in the same position

Anna71 [15]3 years ago

4 0

The floating leaf will move up and down but it will remain in horizontal translation equilibrium

You might be interested in

A cylinder containing an ideal gas has a volume of 2.6 m3 and a pressure of 1.5 × 105 Pa at a temperature of 300 K. The cylinder

frozen [14]

<h2>Answer: $13.5\times 10^{8}$ joules</h2>

Explanation:

From the first law of thermodynamics,

Δ $Q$ =Δ $U$ + $W$

Where $Q$ is the heat given to the gas,

$U$ is the internal energy of the gas,

$W$ is the workdone by the gas.

When pressure is constant,

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

$V_{2}=\frac{2.6\times 900}{300}=7.8m^{3}$

When pressure is constant, $W=P$ Δ $V$

Where $P$ is pressure and $V$ is the volume of the gas.

Given $P=1.5\times 10^{5}Pa$

Δ $V=$ $7.8-2.6=5.2m^{3}$

So, $W=1.5\times 10^{5}\times 5.2=7.8\times 10^{5}J$

Given that Δ $U=6\times 10^{5}$

So,Δ $Q=$ $6\times 10^{5}+7.8\times 10^{5}=13.8\times 10^{5}J$

5 0

3 years ago

(DUE IN FIVE MINUTES, QUICK)

goldfiish [28.3K]

Answer:

Well you would be flouting out in space so it will change your weight a lot because you can't stop moving.

8 0

3 years ago

Read 2 more answers

Examine the weather map and locate this symbol.

DochEvi [55]

The right answer is A

7 0

3 years ago

Read 2 more answers

For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency

Angelina_Jolie [31]

Answer:

2.7 J

Explanation:

The energy of one photon is given by

$E=hf$

where

h is the Planck constant

f is the frequency

For the photons in this problem,

$f=6.8\cdot 10^9 Hz$

So the energy of one photon is

$E_1=(6.63\cdot 10^{-34})(6.8\cdot 10^9 )=4.5\cdot 10^{-24} J$

The number of photons contained in 1.0 mol is

$N_A = 6.022\cdot 10^{23} mol^{-1}$ (Avogadro number)

So the total energy of $N_A$ photons contained in 1.0 mol is

$E=N_A E_1 =(6.022\cdot 10^{23})(4.5\cdot 10^{-24})=2.7 J$

3 0

3 years ago

When the voltage is

gizmo_the_mogwai [7]

Explanation:

ask to nirajan shrestha

search on fb

he is good science teacher❣❣❣

7 0

3 years ago