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3 years ago

It is important to wear protective equipment in both practice and games.

Physics

1 answer:

Ede4ka [16]3 years ago

4 0

Answer:

It is important to wear protective equipments during games and practices.

Explanation:

Practice is a review of what is about to happen in some time to come and with practice ,the future can be trusted.

During practice it is very important to use protective gears or equipments because without them, injuries and accidents are liable to occur.

During the major game it is also important to prevent accidents or big injuries as the equipments protect each vital part of the body.

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When the current in a toroidal solenoid is changing at a rate of 0.0240 A/s , the magnitude of the induced emf is 12.4 mV . When

Gemiola [76]

Answer:

The number of turns in the solenoid is 230.

Explanation:

Given that,

Rate of change of current, $\dfrac{dI}{dt}=0.0240\ A/s$

Induced emf, $\epsilon=12.4\ mV=12.4\times 10^{-3}\ V$

Current, I = 1.5 A

Magnetic flux, $\phi=0.00338\ Wb$

The induced emf through the solenoid is given by :

$\epsilon=L\dfrac{dI}{dt}$

$L=\dfrac{\epsilon}{(di/dt)}$ ........(1)

The self inductance of the solenoid is given by :

$L=\dfrac{N\phi}{I}$ .........(2)

From equation (1) and (2) we get :

$\dfrac{\epsilon}{(di/dt)}=\dfrac{N\phi}{I}$

N is the number of turns in the solenoid

$N=\dfrac{\epsilon I}{\phi (dI/dt)}$

$N=\dfrac{12.4\times 10^{-3}\times 1.5}{0.00338 \times 0.024}$

N = 229.28 turns

N = 230 turns

So, the number of turns in the solenoid is 230. Hence, this is the required solution.

3 0

2 years ago

Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1150 kg and was approaching at

devlian [24]

Force acting during collision is internal so momentum is conserve so (initial momentum = final momentum) in both directions Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1150 kg and was approaching at 5.00 m/s due south. The second car has a mass of 750 kg and was approaching at 25.0 m/s due west. Let Vx is and Vy are final velocities of car in +x and +y direction respectively. initial momentum in +ve x (east) direction = final momentum in +ve x direction (east)

- 750*25 + 1150*0 = (750+1150)
Vx initial momentum in +ve y (north) direction = final momentum in +ve y direction (north)

750*0 - 1150*5 = (750+1150)
Vy from here you can calculate Vx and Vy so final velocity V is

V=(√V2x+V2y)

and angle make from +ve x axis is

θ=tan−1(VyVx)

 kinetic energy loss in the collision = final KE - initial KE

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2 years ago

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saw5 [17]

Will reflect ........

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3 years ago

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d1i1m1o1n [39]

Answer:

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