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lapo4ka [179]
3 years ago
6

Write the cell notation for an electrochemical cell consisting of an anode where Cr2^+(aq) is oxidized to Cr3^+(aq) at a platinu

m electrode and a cathode where Co2^+(aq) is reduced to Co(s) . Assume all aqueous solutions have a concentration of 1 mol/L and gases have a pressure of 1 bar.
Chemistry
1 answer:
Vika [28.1K]3 years ago
3 0

Answer:

Overall cell notation

Cr2^+(aq)/Cr3^+(aq)// Co^2+(aq)/ Co(s)

Explanation:

Let us consider the two half reaction equations:

Oxidation half equation:

2Cr^2+(aq) -------> 2Cr^3+(aq) + 2e

Reduction half equation:

Co^2+(aq) + 2e --------> Co(s)

Overall reaction equation:

2Cr^2+(aq) + Co^2+(aq) ----> 2Cr^3+(aq) + Co(s)

Overall cell notation

Cr2^+(aq)/Cr3^+(aq)// Co^2+(aq)/ Co(s)

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Answer:

HA +  KOH  →  KA  +  H₂O

Explanation:

The unknown solid acid in water can release its proton as this:

HA  +  H₂O  →  H₃O⁺  +  A⁻

As we have the anion A⁻, when it bonded to the cation K⁺, salt can be generated, so the reaction of HA and KOH must be a neutralization one, where you form water and a salt

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It is a neutralization reaction because H⁺ from the acid and OH⁻ from the base can be neutralized as water

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3 years ago
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Explanation:

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