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KonstantinChe [14]
3 years ago
10

Why is it difficult to use the law of conservation of energy to calculate the

Physics
2 answers:
Liula [17]3 years ago
7 0

Answer:

Inelastic collisions actually do conserve energy, but the loss of energy to heat and mechanical vibration is hard to calculate so the math equating energy before and energy after is hard to balance.

Dmitriy789 [7]3 years ago
4 0

<u>Answer:</u>

The law of conservation of energy is difficult to use for calculate the

effects of a collision because of  energy loss

<u>Explanation:</u>

We know that Collisions are of two types which is elastic and inelastic. The Law of Conservation of energy can be defined as in isolated system the total energy is said to remain constant and stays conserved over time can be applied on elastic collisions only as they don't lose energy and can not be applied on inelastic collisions due to energy  loss  in them due to heat and mechanical vibration. Hence, law of conservation of energy can not be used to calculate effects of collision

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Answer:

Chemical energy to electrical energy to mechanical and thermal energy

Explanation:

In the rotating fan, the chemical energy stored in the battery is used to generate electrical energy.

The electrolytes within the battery undergoes chemical reactions that produces electric current.

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  • In like manner, heat energy is also produced.
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Which element has the fewest valence electrons?
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3 years ago
What is the resultant of a pair of forces, 100N, upward and 75N, downward?
soldi70 [24.7K]

Answer:

25N

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3 0
3 years ago
A 950-kg car strikes a huge spring at a speed of 22m/s (fig. 11-54), compressing the spring 5.0m. (a) what is the spring stiffne
alukav5142 [94]

(a) The spring stiffness constant of the spring is 18,392 N/m.

(b) The time the car was in contact with the spring before it bounces off in the opposite direction is 0.23 s.

<h3>Kinetic energy of the car</h3>

The kinetic energy of the car is calculated as follows;

K.E = ¹/₂mv²

K.E = ¹/₂ x 950 x 22²

K.E = 229,900 J

<h3>Stiffness constant of the spring</h3>

The stiffness constant of the spring is calculated as follows;

K.E =  U = ¹/₂kx²

k = 2U/x²

k = (2 x 229,900)/(5)²

k = 18,392 N/m

<h3>Force exerted on the spring</h3>

F = kx

F = 18,392 x 5

F = 91,960 N

<h3>Time of impact</h3>

F = mv/t

t = mv/F

t = (950 x 22)/(91960)

t = 0.23 s

Learn more about spring constant here: brainly.com/question/1968517

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