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KonstantinChe [14]
3 years ago
10

Why is it difficult to use the law of conservation of energy to calculate the

Physics
2 answers:
Liula [17]3 years ago
7 0

Answer:

Inelastic collisions actually do conserve energy, but the loss of energy to heat and mechanical vibration is hard to calculate so the math equating energy before and energy after is hard to balance.

Dmitriy789 [7]3 years ago
4 0

<u>Answer:</u>

The law of conservation of energy is difficult to use for calculate the

effects of a collision because of  energy loss

<u>Explanation:</u>

We know that Collisions are of two types which is elastic and inelastic. The Law of Conservation of energy can be defined as in isolated system the total energy is said to remain constant and stays conserved over time can be applied on elastic collisions only as they don't lose energy and can not be applied on inelastic collisions due to energy  loss  in them due to heat and mechanical vibration. Hence, law of conservation of energy can not be used to calculate effects of collision

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How does the time at which you see things happen at a baseball game compare to the time when you hear things happen? Explain you
hoa [83]

Answer:

Because of the speed of the sound.

Explanation:

The first thing that happens in such cases is to take into account the speed of the sound. First, we see that the player hits the ball with the bat, if we are in the stands far enough we will hear the sound of the batting time later, this time depends on the speed of the sound which is equal to 345 [m/s].

Another visible and practical example is a fireworks display, where people nearby immediately hear the explosion. while those at a great distance will be able to see first the explosion followed by the sound.

With the following equation, we can calculate how long it takes to hear a hit or explosion

t = x / v

where:

x = distance [m]

v = sound velocity = 345 [m/s]

t = time [s]

7 0
3 years ago
Why does a hot-air balloon rise?
prohojiy [21]

Answer: The weight of the air displaced by the balloon is less than the volume of the balloon.

Explanation:

A hot air balloon is a cloth wrap that contains several thousand cubic meters of air inside (a large volume of air). The burner heats the liquid propane to a gaseous state to generate a huge flame, which can reach more than 3 meters, thus heating the air mass inside the balloon. In this way,<u> its density is modified with respect to the air that surrounds it</u>, because the hot air is lighter than the outside air (less dense), causing the balloon to rise and float.

Now, if we know that the density of a body d is directly proportional to its mass m and inversely proportional to its volume V:

d=\frac{m}{V}

We can deduce that <u>by increasing the volume of the body, its density will decrease.</u>

This is proof of <em><u>Archimedes' Principle</u></em>:  

<em>A body totally or partially immersed in a fluid at rest, experiences a vertical upward thrust equal to the mass weight of the body volume that is displaced.</em>

In this case the fluid is the air outside. So, the warm air inside the balloon, being less dense, will weigh less than the outside air and therefore will receive an upward pushing force or thrust that will make the balloon ascend.

4 0
3 years ago
How does an NASCAR works?
mote1985 [20]

Answer:

It works by adding an engine, a transmission, car batteries, an extra strong frame in case of a crash, and much more needed things. When it races, The rubber often burns a lot, because of the high speeds that it goes, so that is why they so often change the tires. They give it a full tank of gas, which is basically like the car's idea of food and water. A NASCAR must have a trong engine to go so fast in order to win a race.

Explanation:

Just think of it like building a lego car just hot gluing the legos together and seeing if it breaks.

6 0
3 years ago
Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin
Alex777 [14]

Answer:

0.92 μC

Explanation:

In a parallel-plate capacitor, the electric field formed is equal to the charge density divited by the vacuum permisivity e0, as there are no dielectric between the plates. e0 is equal to 8.85*10^-12 C^2/Nm^2. The charge density is the total charge of each individual plate divided by its area. Then, the maximum charge allowed will be equal to:

E = \frac{o}{e_0} = \frac{Q}{Ae_0} \\ Q = E*A*e_0 = 3*10^6 N/C * (0.25*\pi *(0.21m)^2)*8.85*10^{-12}C^2/Nm^2 = 9.196 *10^{-7} C

or 0.92 μC

7 0
2 years ago
An astronaut is stationary in space. Which of these would have the greatest speed as observed by the astronaut?
yaroslaw [1]
Hello!

The answer that makes most sense to me is option A.

~ Hope I helped! ~
7 0
3 years ago
Read 2 more answers
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