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kotegsom [21]
3 years ago
12

Soil formation involves both

Physics
1 answer:
Softa [21]3 years ago
6 0
The process of soil formation involves the following steps: Accumulation of materials, leaching and losses (because of weather factors particles are leached and eroded away or taken up from the soil by plants), Transformation and illluviation (the chemical weathering<span> of silt, sand, and the formation of clay minerals as well as the change of organic materials into decay resistant organic matter), p</span>odsolisation and translocations (strong acidic solutions breakdown the clay minerals). From the given options soil formation involves both <span>physical and chemical weathering of rocks. Correct answer:D</span>
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A liquid of density 830 kg/m3 flows through a horizontal pipe that has a cross-sectional area of 1.20 x 10-2 m2 in region A and
kicyunya [14]

Answer:

A) volume flow rate = 0.047 m3/s

B) mass flow rate = 39.01 kg/s

Explanation:

Detailed explanation and calculation is shown in the image below

3 0
3 years ago
I need help with 1-10
e-lub [12.9K]

Answer:

1) C. Energy

2) A. Joule

3) D. Joule

4) B. Potential

5) A. Greater

6) C. Largest

7) A. Speed and mass

8) A. Kinetic

9) A. Kinetic

10) D. Height and mass

3 0
3 years ago
1200kg car speeds up from 2 m/s to 6 m/s. How many times greater is the car's kinetic
Bezzdna [24]

Answer:

9 times as great

Explanation:

KE = 1/2mv²

  1. 1/2(1200)(2)² = 2,400 J
  2. 1/2(1200)(6)² = 21,600 J

21,600 / 2,400 = 9

3 0
3 years ago
What is the relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum? As t
Elanso [62]

<u>Explanation</u>

  • The relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum as the bond strength increases the wave number increases.

                STRENGTH OF BONDS TRIPLE>DOUBLE>SINGLE

                WAVE NUMBER SINGLE>DOUBLE>TRIPLE

  • wave number for single bond is greatest because it has greatest bond frequency among the three( more the frequency greater is the wave number).

8 0
3 years ago
When using a calorimeter, the initial temperature of a metal is 70.4C. The initial temperature of the water is 23.6C. At the end
Sunny_sXe [5.5K]

1) 29.8 C

At the beginning, the metal is at higher temperature (70.4 C) while the water is at lower temperature (23.6 C). When they are put in contact, the metal transfers heat to the water, until they reach thermal equilibrium: at thermal equilibrium the two objects (the metal and the water have same temperature). Therefore, since the temperature of the water at thermal equilibrium is 29.8 C, the final temperature of the metal must be the same (29.8 C).

2) 6.2 C

The temperature change of the water is given by the difference between its final temperature and its initial temperature:

\Delta T = T_f - T_i

where

T_f = 29.8 C\\T_i = 23.6 C

Substituting into the formula,

\Delta T=29.8 C-23.6 C=6.2 C

And the positive sign means that the temperature of the water has increased.

3) -40.6 C

The temperature change of the metal is given by the difference between its final temperature and its initial temperature:

\Delta T = T_f - T_i

where

T_f = 29.8 C\\T_i = 70.4 C

Substituting into the formula,

\Delta T=29.8 C-70.4 C=-40.6 C

And the negative sign means the temperature of the metal has decreased.

5 0
4 years ago
Read 2 more answers
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