The answer to that question is 58.4 g/mol.
Answer:
Equation correctly showing the heat of solution

Explanation:
Mass of aqueous solution = m = 100 g
Specific heat of solution = c = 4.18 J/gºC
Change in temperature = 
ΔT = 21.6ºC - 30.0ºC = -8.4ºC
Heat lost by the solution = Q


Q = -3,511.2 J ≈ -3.51 kJ
Heat absorbed by potassium nitrate when solution in formed; Q'
Q' = -Q = 3.51 kJ
Moles of potassium nitrate , n= 

The heat of solution =

So, the equation correctly showing the heat of solution

Answer:
5.46
Explanation:
From the question,
pH this can be defined as the acidity or alkalinity of a solution.
The expression for pH is given as
pH = -log(H⁺)...................... Equation 1
Where H⁺ = Hydrogen ion of HCL
Given: H⁺ = 3.5×10⁻⁶ M
Substitite this value into equation 1
pH = -log(3.5×10⁻⁶)
pH = 5.46
Hence the pH of HCl is 5.46
Answer: I think probaly wrong so probaly dont
listen to me
Explanation: