In molecules with the same number of electron groups but different molecular geometries, One of the chances is that the central atoms alter in the way in which their electrons are arranged.
Explanation:
- Consider molecules with steric number = four sets of electrons around the central atom.A tetrahedral geometry with 109.5 deg bond angles is predicted by VSEPR
- NH3 is pyramidal with a lone pair on one end of the tetrahedron. The HNH angle is 107.3 deg, generally described by stating that the lone pair is fatter than the pairs that bond.
- PH3 is also pyramidal, the HPH angles are close to being 90-degree angles.
- The assumption is that the small atoms (like C and N) use hybrid sp3 orbitals to form the bonds with hydrogen in their compounds. All N and P merely make three ammonia and phosphine bonds.
- The hydrogens remain further apart if the nitrogen uses hybrid orbitals. Phosphorus is large enough that the hydrogens don’t associate too much in phosphine. Since the P doesn’t have to exhaust the energy required to hybridize its bonding orbitals.
Fusion/Melting Freezing Vaporization/Boiling Condensation Sublimation Deposition Solid to a Liquid Liquid to a Solid Liquid to a Gas Gas to a Liquid Solid to a Gas Gas to a Solid
Answer:
it is he
Explanation:
beacuse Noble gases have 2 volence
Answer:
40.0 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If P and T are constant, and have different values of n and V:
<em>(V₁n₂) = (V₂n₁).</em>
V₁ = 50.0 L, n₁ = 2.0 moles,
V₂ = ??? L, n₂ = 2.0 mol - 0.4 mol = 1.6 mol.
∴ V₂ = (V₁n₂)/(n₁) = (50.0 L)(1.6 mol)/(2.0 mol) = 40.0 L.