If you have 11.2 g of NaCl, how many moles do you have?

Determine which of the following elements would gain electrons when becoming ions: I. Hydrogen II. Helium III. Sulfur IV. Fluori

klio [65]

Hydrogen, iron, and gallium is the correct answer. Hence, option B is correct.

<h3>What is an electron?</h3>

An electron is a negatively charged subatomic particle.

Let us take another look at the periodic table. The periodic table is composed of metals, metalloids and nonmetals.

Metals lose electrons more easily, that is why they form cations. Metals are found on the left-hand side of the periodic table.

As we move away from the left-hand side of the periodic table, the ability to form cations decreases as metallic character decreases and elements become more nonmetallic.

The noble gas helium rarely loses electrons. Fluorine would rather accept an electron to form a negative ion.

Hence, the elements hydrogen, iron and gallium are metals hence they lose electrons more easily.

Hence, option B is correct.

Learn more about the electrons here:

brainly.com/question/1255220

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7 0

2 years ago

What are the chemical properties of beryllium phosphide??

o-na [289]

Answer:

Forms ionic bonds, insoluble, doesn't participate in single or double displacement reactions, non-reactive, high heat of combustion

Explanation:

Beryllium is a metal, since it belongs to group 2A, the alkaline earth metals. It has a total of 2 valence electrons.

Phosphorus, on the other hand, belongs to group 5A and has a total of 5 valence electrons.

We have a compound which has a metal in it, therefore, it's an ionic compound. Beryllium, our metal, loses its 2 electrons to gain an octet and phosphorus, our nonmetal, should gain 3 electrons to have an octet. The oxidation states are +2 and -3 respectively. This means we need 3 beryllium cations and 2 phosphide anions in our formula $Be_3P_2$ .

Beryllium phosphide would be expected to be insoluble, as only beryllium chloride, fluoride, nitrate, phosphate and sulfate are soluble substances, while the remaining ones are expected to be insoluble.

Due to its insolubility, beryllium phosphide would not participate in any ionic reactions, such as single displacement or double displacement.

Since it's insoluble, we expect this compound to be chemically stable and not reactive. This implies that if we wanted to burn it, the heat of combustion would be very high, as a lot of energy would be needed to be supplied in an endothermic reaction in order to burn it.

8 0

3 years ago

Part B When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 22.8 g of carbon were burned in the pres

aksik [14]

<u>Answer:</u> The amount of carbon dioxide gas produced in the reaction is 83.6 grams

<u>Explanation:</u>

As, some amount of oxygen gas is left after the reaction is completed. So, it is present in excess and is considered as an excess reagent.

Thus, carbon is considered as a limiting reagent because it limits the formation of product.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of carbon = 22.8 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

$\text{Moles of carbon}=\frac{22.8g}{12g/mol}=1.9mol$

The chemical equation for the reaction of carbon and oxygen gas follows:

$C+O_2\rightarrow CO_2$

By Stoichiometry of the reaction:

1 mole of carbon produces 1 mole of carbon dioxide gas

So, 1.9 moles of carbon will produce = $\frac{1}{1}\times 1.9=1.9moles$ of carbon dioxide gas

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 1.9 moles

Putting values in equation 1, we get:

$1.9mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(1.9mol\times 44g/mol)=83.6g$

Hence, the amount of carbon dioxide gas produced in the reaction is 83.6 grams

6 0

3 years ago

Can someone do this for me on paper

sertanlavr [38]

Yea same I tried so hard I think you need to get a expert or look this up on a website or something

8 0

3 years ago

What is the molarity of the 8.76 g of Na2S dissolved in 0.500 L of solution?

AlexFokin [52]

Answer:

.224 M

Explanation:

To begin, we need to find the molar mass of Na2S

Na=22.99g, S=78.05g

2(22.99)+1(32.07)=78.05

To find Molarity, we use the equation M=moles/Liters of solution

We are given grams, so we must divide by the molar mass of Na2S to find moles.

8.76g Na2S / 78.05g/mol Na2S= .112 moles

Now we use our Molarity equation:

.112 moles Na2S / .500L of solution = .224 M

6 0

2 years ago