To solve this problem we will consider the concepts related to the normal deformation on a surface, generated when the change in length is taken per unit of established length, that is, the division between the longitudinal fraction gained or lost, over the initial length. In general mode this normal deformation can be defined as

Here,
= Change in final length
and the initial length 
PART A)




PART B)




PART C)




Therefore the rank of this deformation would be B>C>A
Answer:
de 20 miligramos cada pata dividiendo 80÷4=20
Explanation:
Given that,
Mass of the particle, m = 4 kg
Speed of the particle, v = 2.5 m/s
The radius of the circle, r = 2 m
We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :

Substitute all the values,

So, the angular momentum of the particle is 20 kg-m² s.
Explanation:
KE = ½ mv²
130,048 J = ½ m (16 m/s)²
m = 1016 kg