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larisa [96]
3 years ago
12

A(n) ________ system is one in which energy moves freely in and out, but no matter enters or leaves the system.

Physics
2 answers:
alexandr1967 [171]3 years ago
6 0

Answer:

A closed system is one in which energy moves freely in and out, but no matter enters or leaves the system.

Explanation:

In physics, a closed system refers to those that don't aloud certain specific transfer. In this case, a closed system only alows transfer of energy, but transfer of mass is not.

In other words, all systems that don't exchange mass, just energy, they are called closed systems.

It's important to notice that a closed system is not the same as an isolated system, because the last one doesn't a low any kind of transfer, not even mass. That's the difference.

Therefore, in this case, the word that completes the given statement is closed.

3241004551 [841]3 years ago
4 0
A CLOSED SYSTEM. In a closed system in which energy moves freely in and out, but no matter enters or leaves.
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The equation of the energy of a photon is E=h*f.

If we increase the Planck's constant h, the energy would increase. 

For example, lets double the value of Planck's constant and name it H:

H=2*h. Now lets put that into the equation for energy that we will call E₂:

E₂=H*f=2*h*f=2*E. 

So we can clearly see that E₂=2*E or that if we double Planck's constant, the energy also doubles. 
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Answer:

Explanation:

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2 years ago
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A 0.73-m aluminum bar is held with its length parallel to the east-west direction and dropped from a bridge. Just before the bar
Tasya [4]

Answer:

A)  B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West

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A) For this exercise we must use the expression of Faraday's law for a moving body

            fem = -  \frac{d \phi }{dt}

            fem = - \frac{d (B l y}{dt}= - B l v- d (B l y) / dt = - B lv

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we calculate

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the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.

Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West

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3 years ago
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