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larisa [96]
3 years ago
12

A(n) ________ system is one in which energy moves freely in and out, but no matter enters or leaves the system.

Physics
2 answers:
alexandr1967 [171]3 years ago
6 0

Answer:

A closed system is one in which energy moves freely in and out, but no matter enters or leaves the system.

Explanation:

In physics, a closed system refers to those that don't aloud certain specific transfer. In this case, a closed system only alows transfer of energy, but transfer of mass is not.

In other words, all systems that don't exchange mass, just energy, they are called closed systems.

It's important to notice that a closed system is not the same as an isolated system, because the last one doesn't a low any kind of transfer, not even mass. That's the difference.

Therefore, in this case, the word that completes the given statement is closed.

3241004551 [841]3 years ago
4 0
A CLOSED SYSTEM. In a closed system in which energy moves freely in and out, but no matter enters or leaves.
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A carnival merry-go-round rotates about a vertical axis at a constant rate. A man standing on the edge has a constant speed of 3
Advocard [28]

Answer:

r = 5.07 m

Explanation:

given,

velocity of the man , v = 3.43 m/s

centripetal acceleration, a = 2.32 m/s²

magnitude of position of = ?

using centripetal acceleration formula

a_c =\dfrac{v^2}{r}

2.32 =\dfrac{3.43^2}{r}

r =\dfrac{3.43^2}{2.32}

   r = 5.07 m

The magnitude of the position vector relative to rotational axis is equal to 5.07 m.

5 0
3 years ago
A dolphin is able to tell in the dark that the ultrasound echoes received from two sharks come from two different objects only i
Vlad1618 [11]

Answer:

a) Wavelength of the ultrasound wave = 0.0143 m <<< 3.5m, hence its ability is not limited by the ultrasound's wavelength.

b) Minimum time difference between the oscillations = Period of oscillation = 0.00952 ms

Explanation:

The frequency of the ultrasound wave = 105 KHz = 105000 Hz. The speed of ultrasound waves in water ≈ 1500 m/s. Wavelength = ?

v = fλ

λ = v/f = 1500/105000 = 0.0143 m <<< 3.5m

This value, 0.0143m is way less than the 3.5m presented in the question, hence, this ability is not limited by the ultrasound's wavelength.

b) Minimum time difference between the oscillations = The period of oscillation = 1/f = 1/105000 = 0.00000952s = 0.00952 ms

Hope this helps!

6 0
3 years ago
Sarah observed that different kinds and amounts of fossils were present in a cliff behind her house. She wondered if changes in
MAXImum [283]
This is the answer: Fossil's found in Susan's yard are from prehistoric times.
6 0
3 years ago
A person of 70 kg standing on an un-deformable horizontal surface. She bends her knees and jumps up from rest, achieving a launc
eduard

Answer:

1190 N

Explanation:

Force: This can be defined as the product of mass and velocity. The unit of force is Newton(N).

From the question,

F = ma................. Equation 1

Where F = average force, m = mass, a = acceleration.

But,

a = (v-u)/t................ Equation 2

Where v = final velocity, u = initial velocity, t = time.

Substitute equation 2 into equation 1

F = m(v-u)/t.............. Equation 3

Given: m = 70 kg, v = 1.7 m/s, u = 0 m/s (from rest), t = 0.1 s.

Substitute into equation 3

F = 70(1.7-0)/0.1

F = 1190 N.

3 0
3 years ago
A soccer ball with mass 0.450 kg is initially moving with speed 2.20 m/s. A soccer player kicks the ball, exerting a constant fo
Alinara [238K]

Answer:

0.187 m

Explanation:

We'll begin by calculating the acceleration of the ball. This can be obtained as follow:

Mass (m) = 0.450 Kg

Force (F) = 38 N

Acceleration (a) =?

F = m × a

38 = 0.450 × a

Divide both side by 0.450

a = 38 / 0.450

a = 84.44 m/s²

Finally, we shall determine the distance. This can be obtained as follow:

Initial velocity (u) = 2.20 m/s.

Final velocity (v) = 6 m/s

Acceleration (a) = 84.44 m/s²

Distance (s) =?

v² = u² + 2as

6² = 2.2² + (2 × 84.44 × s)

36 = 4.4 + 168.88s

Collect like terms

36 – 4.84 = 168.88s

31.52 = 168.88s

Divide both side by 168.88

s = 31.52 / 168.88

s = 0.187 m

Thus, the distance is 0.187 m

6 0
3 years ago
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