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uranmaximum [27]
3 years ago
11

In a golf ball game, a person hits the golf ball with a club. The club is in contact with the ball, which is initially at rest,

for 2.45 ms. The ball has a mass of 0.0550 kg and leaves the club with a speed of 1.80 X 102 m/s. What is the average force exerted on the ball by the club
Physics
1 answer:
Anon25 [30]3 years ago
6 0

Answer:

F=4040.81 N

Explanation:

Given that

Time ,t= 2.45 ms

Mass ,m= 0.055 kg

v= 1.8 x 10² m/s = 180 m/s

We know that rate of change in the linear momentum is known as force.

Momentum P = m v

F=\dfrac{dP}{dt}

Therefore force F

F=\dfrac{\Delta P}{\Delta t}

F=\dfrac{0.055\times 180}{2.45\times 10^{-3}}\ N

F=4040.81 N

Therefore force on the ball will be 4040.81 N

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Which statement correctly describes the relationship between frequency and wavelength?
Reika [66]

Answer:

Answer:

Option B

Explanation:

Option B talks about how the frequency of the wave increases the shorter it's wavelengths

4 0
2 years ago
A proton moving in the positive x direction with a speed of 9.9 105 m/s experiences zero magnetic force. When it moves in the po
Alex

Answer:

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

Explanation:

In order to calculate the magnitude and direction of the magnetic field, you take into account the following equation for the magnetic force on the proton:

\vec{F_B}=q\vec{v}\ X\ \vec{B}       (1)

v: speed of the proton = 9.9*10^5 m/s

q: charge of the proton = 1.6*10^-19C

B: magnetic field = ?

FB: magnetic force on the proton = 1.6*10^-13N

When the proton travels in the positive y direction (^j), you have that the proton experiences a force in the positive z direction (+^k). To obtain this direction of the magnetic force on the proton, it is necessary that the magnetic field points in the negative x direction, in fact, you have:

^j X (-^i) = -(-^k)=^k

To obtain the magnitude of the magnetic field you use:

F_B=qvBsin90\°=qvB\\\\B=\frac{F_B}{qv}=\frac{1.6*10^{-13}N}{(1.6*10^{-19}C)(9.9*10^5m/s)}\\\\B=1.01T

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

8 0
3 years ago
What is the momentum of an object at rest, in m/s?
Zina [86]

Momentum = (mass) x (speed)

If the speed is zero, then the momentum is zero.

4 0
3 years ago
Just need to confirm an answer
Citrus2011 [14]

Answer:

B

Explanation:

Remark

If, when it reaches its maximum height where the PE is the greatest, that the maximum energy is when the ball is first kicked. That would mean its starting energy is 10 Joules.

Formula

KE = 1/2 m v^2

Givens

KE = 10 J

m = 0.2 kg

v = ?

Solution

10 = 1/2 * 0.2 * v^2

10 * 2 = 0.2 * v^2

20 = 0.2 * v^2

20/0.2 = v^2

100 = v^2

v = 10 m/s

5 0
3 years ago
Convert the Celsius temperature of the surface of the sun, which is
Ghella [55]
So,

The conversion factor is:

F = C *  \frac{9}{5} + 32

So, if we plug in the numbers, we get:
F = 5500 *  \frac{9}{5} +32

Multiply
\frac{5500}{1} * \frac{9}{5} = 9900

Add 32
9900 + 32 = 9932

5500 degrees Celsius = 9932 degrees Farenheit.
5 0
4 years ago
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