Given Information:
Potential difference = V = 7 kV
Magnetic field = B = 0.04 T
Required Information:
Electric Field = E = ?
Answer:
Electric Field = 1.98x10⁶ V/m
Step-by-step explanation:
The required Electric field can be found using
E = vB
Where v is the velocity of electron beam and B is the magnetic field
But first we need to calculate the velocity
V = E/q
E = Vq
Where V is the potential difference and q is the charge 1.60x10⁻¹⁹ C
E = 7x10³*1.60x10⁻¹⁹
E = 11.2x10⁻¹⁶ J
As we know
E = ½mv²
Where m is the mass of electron 9.11x10⁻³¹ kg
v = √2E/m
v = √2*11.2x10⁻¹⁶/9.11x10⁻³¹
v = 4.958x10⁷ m/s
Finally we can now calculate the Electric field
E = vB
E = 4.958x10⁷*0.04
E = 1.98x10⁶ V/m
Therefore, an electric field of 1.98x10⁶ V/m is required if the particles are to be undeflected.
